Java 同时使用多个 Spring PropertyPlaceholderConfigurer
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Multiple Spring PropertyPlaceholderConfigurer at the same time
提问by Amin Abu-Taleb
I have two projects, one of them (Services) includes the second one (Core). I've defined this PropertyPlaceholderConfigurer below within Core project:
我有两个项目，其中一个（服务）包括第二个（核心）。我在 Core 项目中定义了这个 PropertyPlaceholderConfigurer：
<bean id="propertyConfigurer" class="org.springframework.context.support.PropertySourcesPlaceholderConfigurer">
<property name="locations">
<list>
<value>classpath:appConfig.properties</value>
</list>
</property>
</bean>
And I want to extend the Core placeholder in the upper project, including appConfig.properties and some other ones. The only way I found is to define another different bean (different ID) in the upper level and include the new ones:
而且我想在上层项目中扩展Core占位符，包括appConfig.properties和其他一些。我发现的唯一方法是在上层定义另一个不同的 bean（不同的 ID）并包含新的 bean：
<bean id="servicesPropertyConfigurer" class="org.springframework.context.support.PropertySourcesPlaceholderConfigurer">
<property name="locations">
<list>
<value>classpath:swagger.properties</value>
</list>
</property>
</bean>
But it yields it cannot find appConfig.properties, I guess it's only using one of these PropertyPlaceholderConfigurer at the same time? Is it necesary to specify all resources in the upper propertyConfigurer?:
但它会导致它找不到 appConfig.properties，我猜它同时只使用这些 PropertyPlaceholderConfigurer 之一？是否需要在上层propertyConfigurer中指定所有资源？：
<bean id="servicesPropertyConfigurer" class="org.springframework.context.support.PropertySourcesPlaceholderConfigurer">
<property name="locations">
<list>
<value>classpath:swagger.properties</value>
<value>classpath:appConfig.properties</value>
</list>
</property>
</bean>
Is it posible to extend the Core bean o use both at the same time?
是否可以扩展 Core bean 或同时使用两者？
采纳答案by M. Deinum
You can use multiple at the same time BUTyou have to have different names/ids for each else one will override the other. Next to that you need to either use different placeholders (${...}) for each or configure it to ignore unresolved placeholders.
您可以同时使用多个，但您必须为每个名称/ID 使用不同的名称/ID，否则一个将覆盖另一个。接下来，您需要为每个占位符使用不同的占位符 (${...}) 或将其配置为忽略未解析的占位符。
Instead of using the class definition I strongly suggest yo use the namespace (<context:property-placeholder .. />which saves you some xml. (It will generate beans with unique names so you can have multiple at the same time, make sure to set the ignore-unresolvableattribute to true.
我强烈建议<context:property-placeholder .. />您不要使用类定义，而是使用名称空间（它可以为您节省一些 xml。它会生成具有唯一名称的 bean，因此您可以同时拥有多个 bean，确保将ignore-unresolvable属性设置为true.
As a last resort you could implement your a BeanDefinitionRegistryPostProcessorwhich detects all PropertyPlaceHolderConfigurerinstances, merges them into one and move all the locations/resources to the merged one. That way you don't have to worry about multiple different placeholders or unresolvable properties.
作为最后的手段，您可以实现BeanDefinitionRegistryPostProcessor检测所有PropertyPlaceHolderConfigurer实例的 a ，将它们合并为一个并将所有位置/资源移动到合并的一个。这样您就不必担心多个不同的占位符或无法解析的属性。
回答by Ugur Artun
try this code
试试这个代码
<bean id="servicesPropertyConfigurer" class="org.springframework.context.support.PropertySourcesPlaceholderConfigurer">
<property name="locations">
<list>
<value>classpath:swagger.properties</value>
<value>classpath:appConfig.properties</value>
</list>
</property>
<property name="ignoreUnresolvablePlaceholders" value="true"/>
