C# 如何将十六进制值解析为 uint？
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How to parse hex values into a uint?
提问by Cameron A. Ellis
uint color;
bool parsedhex = uint.TryParse(TextBox1.Text, out color);
//where Text is of the form 0xFF0000
if(parsedhex)
//...
doesn't work. What am i doing wrong?
不起作用。我究竟做错了什么？
采纳答案by Nescio
Try
尝试
Convert.ToUInt32(hex, 16) //Using ToUInt32 not ToUInt64, as per OP comment
回答by Corey Ross
Or like
或者喜欢
string hexNum = "0xFFFF";
string hexNumWithoutPrefix = hexNum.Substring(2);
uint i;
bool success = uint.TryParse(hexNumWithoutPrefix, System.Globalization.NumberStyles.HexNumber, null, out i);
回答by Jeremy Wiebe
You can use an overloaded TryParse()which adds a NumberStyle parameter to the TryParsecall which provides parsing of Hexadecimal values. Use NumberStyles.HexNumberwhich allows you to pass the string as a hex number.
您可以使用重载TryParse()将 NumberStyle 参数添加到TryParse提供十六进制值解析的调用中。使用NumberStyles.HexNumber它允许您将字符串作为十六进制数字传递。
Note: The problem with NumberStyles.HexNumberis that it doesn'tsupport parsing values with a prefix (ie. 0x, &H, or #), so you have to strip it off before trying to parse the value.
注意：问题NumberStyles.HexNumber在于它不支持解析带有前缀（即0x, &H, 或#）的值，因此您必须在尝试解析该值之前将其剥离。
Basically you'd do this:
基本上你会这样做：
uint color;
var hex = TextBox1.Text;
if (hex.StartsWith("0x", StringComparison.CurrentCultureIgnoreCase) ||
hex.StartsWith("&H", StringComparison.CurrentCultureIgnoreCase))
{
hex = hex.Substring(2);
}
bool parsedSuccessfully = uint.TryParse(hex,
NumberStyles.HexNumber,
CultureInfo.CurrentCulture,
out color);
See this article for an example of how to use the NumberStyles enumeration: http://msdn.microsoft.com/en-us/library/zf50za27.aspx
有关如何使用 NumberStyles 枚举的示例，请参阅本文：http: //msdn.microsoft.com/en-us/library/zf50za27.aspx
回答by Curtis Yallop
Here is a try-parse style function:
这是一个 try-parse 风格的函数：
private static bool TryParseHex(string hex, out UInt32 result)
{
result = 0;
if (hex == null)
{
return false;
}
try
{
result = Convert.ToUInt32(hex, 16);
return true;
}
catch (Exception exception)
{
return false;
}
}
