将 XML 解析为 Hashmap Java
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Parsing XML into a Hashmap Java
提问by mr Android
I have some information stored in XML, and I need to parse XML and store some of the values in Hashmap. Here is the XML:
我有一些信息存储在 XML 中，我需要解析 XML 并将一些值存储在 Hashmap 中。这是 XML：
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<sections xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<section ID="1">
<Room>Room1</Room>
<Capactiy>25</Capactiy>
<Approval_Mode>personally</Approval_Mode>
<Building>Building1</Building>
<Address>Streer, 1. Stock, links</Address>
<Room_Number>ZA0115</Room_Number>
<CoordLt>16.412094</CoordLt>
<CoordLn>48.19719</CoordLn>
</section>
<section ID="2">
<Room>Room2</Room>
<Capactiy>120</Capactiy>
<Institute>E401</Institute>
<Approval_Mode>personally</Approval_Mode>
<Building>Building2</Building>
<Address>Street 2, Building2, Stiege 7, 1.Stock</Address>
<Room_Number>AH0105</Room_Number>
<CoordLt>16.369865</CoordLt>
<CoordLn>48.199006</CoordLn>
</section>
----
I want that key be:Room1 and values: 16.412094,48.19719 (example for Section ID=1)
我希望该键为：Room1 和值：16.412094,48.19719（部分 ID=1 的示例）
That is example for first section.I have more than 100 section so I would like to store key and values for every section like I explained for the first example.
这是第一部分的示例。我有 100 多个部分，所以我想为每个部分存储键和值，就像我在第一个示例中解释的那样。
Output would be:
输出将是：
Room1: 16.412094,48.19719; Room2: 16.369865,48.199006;
房间1：16.412094,48.19719；Room2：16.369865,48.199006；
Room3: 16,48; . . . Room100: 16,49;
房间3：16,48；. . . Room100：16,49；
Can anyone help me?
谁能帮我？
Here is my code:
这是我的代码：
import java.io.File;
import java.sql.ResultSet;
import java.util.HashMap;
import org.xml.sax.*;
import org.xml.sax.helpers.DefaultHandler;
import javax.xml.parsers.SAXParserFactory;
import javax.xml.parsers.ParserConfigurationException;
import javax.xml.parsers.SAXParser;
public class XML extends DefaultHandler
{
static HashMap<StringBuffer, String> hashMap;
String elementName;
StringBuffer elementValue;
private HashMap<String, String> newMap;
public static void main(String[] args)
{
DefaultHandler handler = new XML();
SAXParserFactory factory = SAXParserFactory.newInstance();
try
{
hashMap = new HashMap<StringBuffer, String>();
//out = new OutputStreamWriter(System.out, "UTF8");
SAXParser saxParser = factory.newSAXParser();
saxParser.parse(new File("xml1.xml"), handler);
System.out.println(hashMap);
}
catch(Throwable t)
{
t.printStackTrace();
}
System.exit(0);
}
public void startElement(String namespaceURI, String sName, String qName, Attributes attrs)
throws SAXException
{
String eName = sName;
if("".equals(eName)) eName = qName;
elementName = eName;
if(attrs != null)
{
for(int i = 0; i < attrs.getLength(); i++)
{
String aName = attrs.getLocalName(i);
if("".equals(aName)) aName = attrs.getQName(i);
}
}
}
public void endElement(String namespaceURI, String sName, String qName)
throws SAXException
{
String eName = sName;
if("".equals(eName)) eName = qName;
if(eName.equals(elementName))
hashMap.put(elementValue,""+ elementName );
elementValue = null;
}
public void characters(char[] ch, int start, int length)
throws SAXException
{
String str = new String(ch, start, length);
if(elementValue == null)
elementValue = new StringBuffer(str);
else
elementValue.append(str);
}
}
With this code I don't get desired output. output is: Room=Room1, Capacity=25......
使用此代码，我没有得到所需的输出。输出为：房间=房间1，容量=25......
回答by Fathah Rehman P
Assume your xml file is "c:/test.xml"
假设您的 xml 文件是“c:/test.xml”
Then use the following code to read and put into a hash map in in the following format as you said
key=Roomnumber value=CoordLt,CoordLn
然后使用下面的代码按照你说的
key=Roomnumber value=CoordLt,CoordLn读取并放入以下格式的哈希映射
import java.io.File;
import java.io.IOException;
import java.util.HashMap;
import java.util.logging.Level;
import java.util.logging.Logger;
import javax.naming.spi.DirStateFactory.Result;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import javax.xml.transform.OutputKeys;
import javax.xml.transform.Source;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerConfigurationException;
import javax.xml.transform.TransformerException;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.dom.DOMSource;
import javax.xml.transform.stream.StreamResult;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.SAXException;
public class xml {
public static void main(String[] args)
{
HashMap<String,String>hMap=new HashMap<String, String>();
File file=new File("c:/test.xml");
if(file.exists())
{
DocumentBuilderFactory factory=DocumentBuilderFactory.newInstance();
try
{
DocumentBuilder builder = factory.newDocumentBuilder();
Document document=builder.parse(file);
Element documentElement=document.getDocumentElement();
NodeList sList=documentElement.getElementsByTagName("section");
if (sList != null && sList.getLength() > 0)
{
for (int i = 0; i < sList.getLength(); i++)
{
Node node = sList.item(i);
if(node.getNodeType()==Node.ELEMENT_NODE)
{
Element e = (Element) node;
NodeList nodeList = e.getElementsByTagName("Room");
String roomName= nodeList.item(0).getChildNodes().item(0)
.getNodeValue();
nodeList = e.getElementsByTagName("CoordLt");
String coordValues= nodeList.item(0).getChildNodes().item(0)
.getNodeValue();
nodeList = e.getElementsByTagName("CoordLn");
coordValues=coordValues+","+ nodeList.item(0).getChildNodes().item(0)
.getNodeValue();
hMap.put(roomName, coordValues);
}
}
}
} catch(Exception e){
System.out.println("exception occured");
}
}else
{
System.out.println("File not exists");
}
}
}
回答by rene
If you transform the XML using this xslt (which can be done in Java) you get your desired output, If someone sle knows howto load in a hashmap you'll be fine.
如果您使用此 xslt（可以在 Java 中完成）转换 XML，您将获得所需的输出，如果有人知道如何加载哈希映射，您会没事的。
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" indent="no" omit-xml-declaration ="yes" />
<xsl:template match="/sections">
<xsl:apply-templates select="section"/>
</xsl:template>
<xsl:template match="section" xml:space="default">
<xsl:apply-templates select="Room"/>
<xsl:text>:</xsl:text>
<xsl:apply-templates select="CoordLt" />
<xsl:text>,</xsl:text>
<xsl:apply-templates select="CoordLn"/>
<xsl:text>;</xsl:text>
</xsl:template>
</xsl:stylesheet>
