Ruby Time.parse 给我超出范围的错误
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Ruby Time.parse gives me out of range error
提问by Tony
I am using Time.parse to create a Time object from a string.
我正在使用 Time.parse 从字符串创建一个 Time 对象。
For some reason
因为某些原因
Time.parse("05-14-2009 19:00")
causes an argument our of range error, whereas
导致参数 our of range 错误，而
Time.parse("05-07-2009 19:00")
does not
才不是
Any ideas?
有任何想法吗？
采纳答案by Brandon
My guess would be that its expecting the second part of the string (the 14) to be the month.
我的猜测是它期望字符串的第二部分（14）是月份。
回答by Miquel
If you know the format of the string use:
如果您知道字符串的格式，请使用：
Time.strptime(date, format, now=self.now) {|year| ...}
http://www.ruby-doc.org/core-1.9/classes/Time.html#M000266
http://www.ruby-doc.org/core-1.9/classes/Time.html#M000266
It will solve your problem and will probably be faster than Time.parse.
它将解决您的问题，并且可能比Time.parse.
EDIT:
编辑：
Looks like they took strptimefrom Time class, but it called Date.strptimeanyway. If you are on Rails you can do:
看起来他们是strptime从 Time 课上学来的，但它还是调用Date.strptime了。如果你在 Rails 上，你可以这样做：
Date.strptime("05-14-2009 19:00","%m-%d-%Y %H:%M").to_time
if you use pure ruby then you need:
如果您使用纯红宝石，那么您需要：
require 'date'
d=Date._strptime("05-14-2009 19:00","%m-%d-%Y %H:%M")
Time.utc(d[:year], d[:mon], d[:mday], d[:hour], d[:min],
d[:sec], d[:sec_fraction], d[:zone])
回答by Oinak
It's because of the heuristics of Time#parse.
这是因为Time#parse.
And it's due to anglo-american formats.
这是由于英美格式。
With dashes '-' it expects mm-dd-yyyy, with slashes '/' it expects dd/mm/yyyy.
破折号“-”预期为mm-dd-yyyy，斜线“/”预期为dd/mm/yyyy。
This behaviour changesintentionally in 1.9. to accomplish eur, iso and jp date standards.
此行为在 1.9 中有意更改。达到 eur、iso 和 jp 日期标准。
回答by Jonas Elfstr?m
回答by James Avery
It is probably expecting Day-Month-Year format, so your first value is trying to specify the 5th day of the 14th month.
它可能需要 Day-Month-Year 格式，因此您的第一个值是尝试指定第 14 个月的第 5 天。
