php 检查 Youtube 和 Vimeo-clips 是否有效
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Check if Youtube and Vimeo-clips are valid
提问by Johan
I have been trying for quite a while to check if submitted links are valid film-clips from youtube.com or vimeo.com but I didn't succeed.
我一直在尝试检查提交的链接是否是来自 youtube.com 或 vimeo.com 的有效电影剪辑，但我没有成功。
Any ideas how to check url's like:
任何想法如何检查网址，如：
http://www.youtube.com/watch?v=jc0rnCBCX2c&feature=fvhl (valid)
http://www.youtube.com/watch?v=jc0FFCBCX2c&feature=fvhl (not valid)
http://www.youtube.com/v/jc0rnCBCX2c (valid)
http://www.youtube.com/v/ddjcddddX2c (not valid)
http://www.vimeo.com/463l522 (not valid)
http://www.vimeo.com/1483909 (valid)
http://www.vimeo.com/lumiblue (not valid)
http://www.youtube.com/user/dd181921 (not valid)
?
?
I use php.
我使用php。
采纳答案by Haim Evgi
i see a answer in this site : www.experts-exchange.com/Programming/Languages/Scripting/JavaScript/Q_23765374.html
我在这个网站上看到了一个答案：www.experts-exchange.com/Programming/Languages/Scripting/JavaScript/Q_23765374.html
and he said :
他说：
I would suggest using youtube's API since you are trying to validate if the video exists. or if you don't want to go into API stuff then you can do simple trick. check this link:
我建议使用 youtube 的 API，因为您正在尝试验证视频是否存在。或者如果你不想进入 API 的东西，那么你可以做一些简单的技巧。检查此链接：
http://code.google.com/apis/youtube/developers_guide_php.html#RetrievingVideoEntry
http://code.google.com/apis/youtube/developers_guide_php.html#RetrievingVideoEntry
to check for the existence of a video you will need to extract "v" value and send a request that contains the video id to :
要检查视频是否存在，您需要提取“v”值并将包含视频 ID 的请求发送到：
http://gdata.youtube.com/feeds/api/videos/videoID
http://gdata.youtube.com/feeds/api/videos/videoID
where videoID is the "v" value for example a video FLE2htv9oxc will be queried like this http://gdata.youtube.com/feeds/api/videos/FLE2htv9oxcif it does not exist then you will get a page with "Invalid id" if it exists, will return an XML feed having various info about the video. this way you can check that the video exists.
其中 videoID 是“v”值，例如视频 FLE2htv9oxc 将像这样查询 http://gdata.youtube.com/feeds/api/videos/FLE2htv9oxc如果它不存在，那么您将获得一个带有“无效 ID”的页面" 如果存在，将返回包含有关视频的各种信息的 XML 提要。这样您就可以检查视频是否存在。
hope this will get you in the right direction.
希望这会让你朝着正确的方向前进。
the same thing with vimeo , try to look in api documentation in there site. http://www.vimeo.com/api
与 vimeo 相同，请尝试查看该站点中的 api 文档。 http://www.vimeo.com/api
回答by chrismacp
If you check the response headers from a request to http://gdata.youtube.com/feeds/api/videos/videoIdwhere videoId is the google video Identifier, you should get a 200 if the video exists and a 400 (bad request) if the video doesn't exist.
如果您检查来自对http://gdata.youtube.com/feeds/api/videos/videoId的请求的响应标头，其中 videoId 是谷歌视频标识符，如果视频存在，您应该得到 200（错误请求） ) 如果视频不存在。
// PHP code
// Check if youtube video item exists by the existance of the the 200 response
$headers = get_headers('http://gdata.youtube.com/feeds/api/videos/' . $youtubeId);
if (!strpos($headers[0], '200')) {
echo "The YouTube video you entered does not exist";
return false;
}
回答by jason
I wrote this function to check if the link is a valid youtube link.
我编写了这个函数来检查链接是否是有效的 youtube 链接。
/**
* This function will check if 'url' is valid youtube video and return the ID.
* If the return value === false then this is **not** a valid youtube url, otherwise the youtube id is returned.
*
* @param <type> $url
* @return <type>
*/
private static function get_youtube_id($url) {
$link = parse_url($url,PHP_URL_QUERY);
/**split the query string into an array**/
if($link == null) $arr['v'] = $url;
else parse_str($link, $arr);
/** end split the query string into an array**/
if(! isset($arr['v'])) return false; //fast fail for links with no v attrib - youtube only
$checklink = YOUTUBE_CHECK . $arr['v'];
//** curl the check link ***//
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL,$checklink);
curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
curl_setopt($ch, CURLOPT_TIMEOUT, 5);
$result = curl_exec($ch);
curl_close($ch);
$return = $arr['v'];
if(trim($result)=="Invalid id") $return = false; //you tube response
return $return; //the stream is a valid youtube id.
}
回答by MANCHUCK
You can try to catch the 301 header that you tube throws if the video is no longer valid
如果视频不再有效，您可以尝试捕获您管抛出的 301 标头
回答by Carca
/*
* Verify YouTube video status
*/
$videoID = "o8UCI7r1Aqw";
$header = get_headers("http://gdata.youtube.com/feeds/api/videos/". $videoID);
switch($headers[0]) {
case '200':
// video valid
break;
case '403':
// private video
break;
case '404':
// video not found
break;
default:
// nothing above
break;
}
