ios 如何在精灵套件中旋转精灵节点？
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How to rotate a sprite node in sprite kit?
提问by Vince
I am making a game and I'm having troubles with rotating a sprite node, This is the code I have; What do I have to add to turn it, let's say 45 degrees?.
我正在制作游戏，但在旋转精灵节点时遇到问题，这是我的代码；我必须添加什么才能转动它，比如说 45 度？
SKSpriteNode *platform = [SKSpriteNode spriteNodeWithImageNamed:@"YellowPlatform.png"];
platform.position = CGPointMake(CGRectGetMidX(self.frame), -200+CGRectGetMidY(self.frame));
platform.size = CGSizeMake(180, 10);
platform.physicsBody = [SKPhysicsBody bodyWithRectangleOfSize:platform.size];
platform.physicsBody.dynamic = NO;
[self addChild:platform];
采纳答案by BSevo
You make SKAction for the rotation and run that action on the node. for example:
您为轮换制作 SKAction 并在节点上运行该操作。例如：
//M_PI/4.0 is 45 degrees, you can make duration different from 0 if you want to show the rotation, if it is 0 it will rotate instantly
SKAction *rotation = [SKAction rotateByAngle: M_PI/4.0 duration:0];
//and just run the action
[yourNode runAction: rotation];
回答by quaertym
Just do this without using actions:
只需执行此操作而不使用操作：
sprite.zRotation = M_PI / 4.0f;
And in Swift 4:
在 Swift 4 中：
sprite.zRotation = .pi / 4
回答by ZeMoon
Using the predefined value will be faster:
使用预定义值会更快：
sprite.zRotation = M_PI_4;
These predefined constants in math.h are available as literals and can be used to reduce actual processing of values like M_PI / 4.0
math.h 中的这些预定义常量可用作文字，可用于减少对 M_PI / 4.0 等值的实际处理
回答by J. V.
sprite.zRotation = M_PI_4;
and
和
[sprite runAction:[SKAction rotateByAngle:M_PI_4 duration:0]];
are not the same.
不一样。
running the SKAction will animate the change even if the duration is 0 it will do it over very short time. changing the zRotation will show it in the new rotation.
即使持续时间为 0，运行 SKAction 也会为更改设置动画，它会在很短的时间内完成。更改 zRotation 将在新的旋转中显示它。
why this is important: if you add new sprite doing on it [SKAction rotateByAngle:] will create flickering/ugliness in the sprite as it comes on the view.
为什么这很重要：如果你在它上面添加新的精灵 [SKAction rotateByAngle:] 会在精灵出现在视图中时产生闪烁/丑陋。
if the sprite is on the screen and you want to rotate it changing the zRotation will not be as nice as rotatebyAngle: even with 0 duration.
如果精灵在屏幕上并且您想旋转它，则更改 zRotation 不会像 rotatebyAngle 那样好：即使持续时间为 0。
回答by Dave Levy
In Swift 4 the way I got mine to rotate was
在 Swift 4 中，我让我的旋转方式是
sprite.zRotation = .pi / 2 // 90 degrees
sprite.zRotation = .pi / 4 // 45 degrees
回答by wm.p1us
For SWIFT 3 / SWIFT 4version you could use next:
对于SWIFT 3 / SWIFT 4版本，您可以使用下一个：
sprite.zRotation = .pi / 4
or if you like actions:
或者如果你喜欢行动：
let rotateAction = SKAction.rotate(toAngle: .pi / 4, duration: 0)
sprite.run(rotateAction)
回答by Chigo Godwin Anyaso
//rotates player node 90 degrees
player.zRotation = CGFloat(M_PI_2)*3;
//rotates 180 degrees
player.zRotation = CGFloat(M_PI_2)*2;
//rotates 270 degrees
player.zRotation = CGFloat(M_PI_2)*1;
//rotates 360 degrees (where it was originally)
player.zRotation = CGFloat(M_PI_2)*4;
//rotates 315 degrees
player.zRotation = (CGFloat(M_PI_2)*1)/2;
and so on...
