java 如何从 Android 中的 Fragment 调用 ArrayAdapter 构造函数
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how to call ArrayAdapter constructer from Fragment in Android
提问by Arif YILMAZ
I am trying to add a two-column ListView to my android app. When I created the project, I selected the option Fragment which creates that beautiful navigation by sliding to left and right. So my MainActivityextends FragmentActivity.
我正在尝试向我的 android 应用程序添加一个两列 ListView。当我创建项目时，我选择了选项 Fragment，它通过向左和向右滑动来创建漂亮的导航。所以我的MainActivity扩展FragmentActivity。
my problem is when I am trying to add AddayAdapter to ListView, the construstor of ArrayAdapter looks for a context object and I dont know to pass that.
我的问题是当我尝试将 AddayAdapter 添加到 ListView 时，ArrayAdapter 的构造函数会查找上下文对象，但我不知道要传递它。
here is the code where I get error
这是我出错的代码
StableArrayAdapter adapter = new StableArrayAdapter(this, R.layout.row , list);
listview.setAdapter(adapter);
When I pass "this", it passes FragmentActivity because the activity extends FragmentActivity. but constructor need a "Context" object.
当我传递“this”时，它传递 FragmentActivity，因为该活动扩展了 FragmentActivity。但是构造函数需要一个“上下文”对象。
it gives this error message
它给出了这个错误信息
"The constructor MainActivity.StableArrayAdapter(MainActivity.DummySectionFragment, int, ArrayList<String>) is undefined"
How can I pass Context object?
如何传递 Context 对象？
回答by Neoh
You are setting the adapter inside a fragment. Use
您正在片段内设置适配器。利用
StableArrayAdapter adapter = new StableArrayAdapter(this.getActivity(), R.layout.row , list);
回答by Thalaivar
StableArrayAdapter adapter = new StableArrayAdapter(getContext(), R.layout.row , list);
listview.setAdapter(adapter);
Did you try passing something like this from your Fragment. Try either getContext()or getApplicationContext().
你有没有尝试从你的 Fragment 传递这样的东西。尝试getContext()或getApplicationContext()。
