Java 如何在 Android Studio 上使用 View Parameter 调用方法
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How to call method with View Parameter on Android Studio
提问by user2565280
I want to call this method
我想调用这个方法
public void openButton(View view) {
Intent intent = new Intent(this, MainActivity.class);
this.startActivity(intent);
}
from simple method like this
从这样的简单方法
public void simple(){
openButton();
}
but I can't do it because openButton needs one parameter View. How?
但我不能这样做，因为 openButton 需要一个参数 View。如何？
采纳答案by Alex K
Well, with the code that you provided, you usually use some sort of an onCickListener.
好吧，对于您提供的代码，您通常会使用某种onCickListener.
Open your XML file, and add android:onClick="openButton"to the button that you want to call that method. So your XML for the button will look something like this:
打开您的 XML 文件，并添加android:onClick="openButton"到您要调用该方法的按钮。因此，按钮的 XML 将如下所示：
<Button
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="Click me!"
. . .
android:onClick="openButton" />
That will automatically call that method and pass in a view.
这将自动调用该方法并传入一个视图。
The other option, as BatScream mentioned in the comments, is to just pass in null, as you aren't using the view anyway. HOWEVER, this is bad practice - it'll work this time, but in general, you should follow the system that Android uses. Just go with an onClickin the XML.
另一种选择，正如 BatScream 在评论中提到的，只是传入null，因为无论如何你都没有使用视图。然而，这是不好的做法 - 这次它会起作用，但总的来说，您应该遵循 Android 使用的系统。只需onClick在 XML 中使用 。
If you HAVE to use simplethe way it is, do it this way:
如果您必须使用simple它的方式，请这样做：
public void simple(){
openButton(null);
}
回答by codeMagic
You should be able to do
你应该能够做到
button.performClick();
assuming openButton()is the method assigned to buttons onClick. Meaning, somewhere in your xml you probably have a Buttonwith android:onClick="openButton". Then if you have that Buttoninstantiated and assigned to the variable button, calling the View's performClick()method would call openButton()
假设openButton()是分配给buttons的方法onClick。意思是，在您的 xml 中的某个地方，您可能有一个Buttonwith android:onClick="openButton". 然后，如果您已将其Button实例化并分配给变量button，则调用View的performClick()方法将调用openButton()
回答by Chintan Soni
Simple. Just pass the view in arguments.
简单的。只需在参数中传递视图。
Way 1:if you are calling openButton()method from layout file then, simply call method the following way by applying onClick attribute
方式 1：如果您openButton()从布局文件调用方法，只需通过应用 onClick 属性按以下方式调用方法
<Button
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="Go to next screen"
. . .
android:onClick="openButton" />
Way 2:if you are trying to call it from button's onclick by setting OnClickListener, then, simply pass the view you are getting inside OnClickListener's onClick(View view)method as follows:
方式 2：如果您尝试通过设置 OnClickListener 从按钮的 onclick 调用它，则只需按如下方式传递您正在进入的视图OnClickListener的onClick(View view)方法：
button.setOnClickListener(new OnClickListener(){
@override
public void onClick(View view)
{
openButton(view);
}
});
