C++ 没有重载函数的实例与参数列表匹配。
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No instance of overloaded function matches argument list.
提问by K455306
I'm working on a project for class, but keep getting the error: no instance of overloaded function matches argument list. It is referencing my String classes. What I am trying to do is create a Copy, Concat and Count functions with out using the string class. Any help would be greatly appreciated.
我正在处理一个类项目，但不断收到错误消息：没有重载函数的实例与参数列表匹配。它引用了我的 String 类。我想要做的是创建一个 Copy、Concat 和 Count 函数而不使用字符串类。任何帮助将不胜感激。
#define _CRT_SECURE_NO_WARNINGS
#include <iostream>
#include <string>
using namespace std;
class String
{
private:
char str[100];
char cpy[100];
public:
static const char NULLCHAR = 'String Copy(char* orig)
{
// Same copy logic you have,
// except copy into "*this"
}
';
String()
{
str[0] = NULLCHAR;
cpy[0] = NULLCHAR;
}
String(char* orig, char* cpy)
{
Copy(orig, cpy);
}
void Display()
{
cout << str << endl;
}
void Copy(char* orig, char* dest)
{
while (*orig != '##代码##') {
*dest++ = *orig++;
}
*dest = '##代码##';
}
void Copy(String& orig, String& dest)
{
Copy(orig.str, dest.cpy);
}
void Concat(char* orig, char* cpy)
{
while (*orig)
orig++;
while (*cpy)
{
*orig = *cpy;
cpy++;
orig++;
}
*orig = '##代码##';
}
void Concat(String& orig, String& cpy)
{
Concat(orig.str, cpy.cpy);
}
int Length(char* orig)
{
int c = 0;
while (*orig != '##代码##')
{
c++;
*orig++;
}
printf("Length of string is=%d\n", c);
return(c);
}
};
int main()
{
String s;
s.Copy("Hello");
s.Display();
s.Concat(" there");
s.Display();
String s1 = "Howdy";
String s2 = " there";
String s3;
String s4("This String built by constructor");
s3.Copy(s1);
s3.Display();
s3.Concat(s2);
s3.Display();
s4.Display();
system("pause");
return 0;
}
回答by Dagrooms
It looks like your Copyand Concatfunctions each take two parameters, yet you pass them both a single parameter. If you want to copy them into a String object, your code should look more like:
看起来您的Copy和Concat函数每个都有两个参数，但是您将它们都传递给一个参数。如果要将它们复制到 String 对象中，您的代码应该更像：
回答by Aakash Arayambeth
As the error message says, There is no version of the constructor for your String class that takes a single parameter. You have a default constructor and one that takes two parameters.
正如错误消息所说，您的 String 类没有采用单个参数的构造函数版本。您有一个默认构造函数和一个带有两个参数的构造函数。
You need to define one which takes a single parameter and initializes the str
您需要定义一个接受单个参数并初始化 str
回答by shiningstarpxx
String s4("This String built by constructor"); this statement needs construction function
String s4("此字符串由构造函数构建"); 这个语句需要构造函数
String(char *);
字符串（字符*）；
