C++ 非标准语法；使用“&”创建指向成员的指针
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non-standard syntax; use '&' to create a pointer to member
提问by M.REB
I'm sure about my function , but I didn't know the meaning of this error
我确定我的函数，但我不知道这个错误的含义
"non-standard syntax; use '&' to create a pointer to member"
this is my function : recherche d'un trajets dans un vector du trajets
这是我的职能：recherche d'un trajets dans un vector du trajets
int compagnie::rechercher_Trajet(int ind)
{
for (int i = 0; i < tab_Trj.size(); i++)
{
if (tab_Trj[i]->getNum == ind)
return i;
return -1 ;
}
}
class trajets :
int getNum() { return numero; }
};
am asking for your help , thnx
我在寻求你的帮助，谢谢
回答by David Haim
well...
好...
if (tab_Trj[i]->getNum() == ind)
you forgot the ().
你忘记了()。
also, in the C++ world, I would advise against writing for (int..., prefer autoor size_tinstead of int. comparing signed and unsigned values can lead to errors.
此外，在C ++的世界里，我会建议对写作for (int...，喜欢auto或size_t代替int。比较有符号和无符号值可能会导致错误。
PS. it is extremly not common to name entities in your program in a language which is not english. also, you are mixing underscore-convention with lower camel case-convention.
附注。在程序中用非英语语言命名实体是非常不常见的。此外，您正在将下划线约定与较低的骆驼案例约定混合在一起。
I'd name the function either rescanTargetor rescan_target, but not rescan_Target(which I believe is the translation for "rechercher_Trajet"?).
我将函数命名为rescanTargetor rescan_target，但不是rescan_Target（我认为这是“rechercher_Trajet”的翻译？）。
