如何在 BASH 中将 md5 sum 编码为 base64
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How to encode md5 sum into base64 in BASH
提问by Rusty Horse
I need to encode md5 hash to base 64. The problem is that if give output of md5sum command to base64 command, it is considered as a text and not as a hexadecimal data. How to manage it? Base64 command has no option to set it's input as a hexadecimal number.
我需要将 md5 哈希编码为 base 64。问题是，如果将 md5sum 命令的输出提供给 base64 命令，它被视为文本而不是十六进制数据。如何管理？Base64 命令没有将其输入设置为十六进制数的选项。
Thanks for any help.
谢谢你的帮助。
回答by plundra
Use openssl dgst -md5 -binaryinstead of md5sum. If you want, you can use it to base64-encode as well, to only use one program for all uses.
使用openssl dgst -md5 -binary代替md5sum。如果您愿意，您也可以使用它进行 base64 编码，以便所有用途仅使用一个程序。
echo -n foo | openssl dgst -md5 -binary | openssl enc -base64
echo -n foo | openssl dgst -md5 -binary | openssl enc -base64
(openssl md5instead of openssl dgst -md5works too, but I think it's better to be explicit)
（openssl md5而不是也openssl dgst -md5有效，但我认为最好是明确的）
回答by BeniBela
You can also use xxd (comes with vim) to decode the hex, before passing it to base64:
在将十六进制传递给 base64 之前，您还可以使用 xxd（与 vim 一起提供）解码十六进制：
(echo 0:; echo -n foo | md5sum) | xxd -rp -l 16 | base64
回答by Paused until further notice.
unhex ()
{
for ((b=0; b<${#1}; b+=2))
do
printf "\x${1:$b:2}";
done
}
md5sum2bytes ()
{
while read -r md5sum file; do
unhex $md5sum;
done
}
md5sum inputfile | md5sum2bytes | base64
回答by mikentalk
In busybox you might not be able to use for loop syntax. Below unhex() is implemented with a while loop instead:
在 busybox 中，您可能无法使用 for 循环语法。下面的 unhex() 是用 while 循环实现的：
unhex ()
{
b=0;
while [ $b -lt ${#1} ];
do
printf "\x${1:$b:2}";
b=$((b += 2));
done
}
md5sum2bytes ()
{
while read -r md5sum file; do
unhex $md5sum;
done
}
md5sum inputfile | md5sum2bytes | base64
