批量重命名文件夹中的文件 - PHP
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Bulk Rename Files in a Folder - PHP
提问by user580950
I have 1000 images in a Folder, which has SKU# word in all the images. For examples
我在一个文件夹中有 1000 张图像，所有图像中都有 SKU# 字样。举些例子
WV1716BNSKU#.zoom.1.jpg
WV1716BLSKU#.zoom.3.jpg
what i need to do is read all the filenames and rename it to the following
我需要做的是读取所有文件名并将其重命名为以下内容
WV1716BN.zoom.1.jpg
WV1716BL.zoom.3.jpg
So remove SKU# from filename, is it possible in PHP to do bulk renaming ?
那么从文件名中删除 SKU#，是否可以在 PHP 中进行批量重命名？
回答by Aston
Yeah, just open the directory and create a loop to access all images and rename them, like:
是的，只需打开目录并创建一个循环来访问所有图像并重命名它们，例如：
<?php
if ($handle = opendir('/path/to/files')) {
while (false !== ($fileName = readdir($handle))) {
$newName = str_replace("SKU#","",$fileName);
rename($fileName, $newName);
}
closedir($handle);
}
?>
References:
参考：
http://php.net/manual/en/function.rename.php
http://php.net/manual/en/function.rename.php
http://php.net/manual/en/function.readdir.php
http://php.net/manual/en/function.readdir.php
回答by Kamil Tom?ík
piece of cake:
小菜一碟：
foreach (array_filter(glob("$dir/WV1716B*.jpg") ,"is_file") as $f)
rename ($f, str_replace("SKU#", "", $f));
(or $dir/*.jpgif number doesn't matter)
（或者$dir/*.jpg如果数字无关紧要）
回答by ircmaxell
Well, using iterators:
好吧，使用迭代器：
class SKUFilterIterator extends FilterIterator {
public function accept() {
if (!parent::current()->isFile()) return false;
$name = parent::current()->getFilename();
return strpos($name, 'SKU#') !== false;
}
}
$it = new SkuFilterIterator(
new DirectoryIterator('path/to/files')
);
foreach ($it as $file) {
$newName = str_replace('SKU#', '', $file->getPathname());
rename($file->getPathname(), $newName);
}
The FilterIterator basically filters out all non-files, and files without the SKU#in them. Then all you do is iterate, declare a new name, and rename the file...
FilterIterator 基本上过滤掉所有非文件，以及其中没有的文件SKU#。然后你要做的就是迭代，声明一个新名称，然后重命名文件......
Or in 5.3+ using the newGlobIterator:
或者在 5.3+ 中使用新的GlobIterator：
$it = new GlobIterator('path/to/files/*SKU#*');
foreach ($it as $file) {
if (!$file->isFile()) continue; //Only rename files
$newName = str_replace('SKU#', '', $file->getPathname());
rename($file->getPathname(), $newName);
}
回答by RobertPitt
The steps to completing this is pretty simple:
完成此操作的步骤非常简单：
- iterate over each file using
fopen,readdir - for each file parse the file name into segments
- copy the old file into a new directly called old (sanity reasons)
- rename the root file top the new name.
- 使用
fopen,迭代每个文件readdir - 对于每个文件，将文件名解析为段
- 将旧文件复制到一个直接称为旧的新文件中（理智原因）
- 将根文件重命名为新名称。
A small example:
一个小例子：
if ($handle = opendir('/path/to/images'))
{
/* Create a new directory for sanity reasons*/
if(is_directory('/path/to/images/backup'))
{
mkdir('/path/to/images/backup');
}
/*Iterate the files*/
while (false !== ($file = readdir($handle)))
{
if ($file != "." && $file != "..")
{
if(!strstr($file,"#SKU"))
{
continue; //Skip as it does not contain #SKU
}
copy("/path/to/images/" . $file,"/path/to/images/backup/" . $file);
/*Remove the #SKU*/
$newf = str_replace("#SKU","",$file);
/*Rename the old file accordingly*/
rename("/path/to/images/" . $file,"/path/to/images/" . $newf);
}
}
/*Close the handle*/
closedir($handle);
}
回答by a.4j4vv1
You can also use this sample:
您还可以使用此示例：
$directory = 'img';
$gallery = scandir($directory);
$gallery = preg_grep ('/\.jpg$/i', $gallery);
// print_r($gallery);
foreach ($gallery as $k2 => $v2) {
if (exif_imagetype($directory."/".$v2) == IMAGETYPE_JPEG) {
rename($directory.'/'.$v2, $directory.'/'.str_replace("#SKU","",$v2));
}
}
