使用 grep 和 cut 定界符命令（在 bash shell 脚本 UNIX 中） - 并且有点“反转”它？

Using the grep and cut delimiter command (in bash shell scripting UNIX) - and kind of "reversing" it?

提问by DeaIss

So I have a file with the text:

所以我有一个带有文本的文件：

puddle2_1557936:/home/rogers.williams/folderz/puddle2

I want to use the grep command

我想使用 grep 命令

grep puddle2_1557936

Mixed in with the cut command (or another command if neccessary) to display just this part:

与 cut 命令（或其他命令，如果需要）混合以仅显示此部分：

/home/rogers.williams/folderz/puddle2

So far, I know that if do this

到目前为止，我知道如果这样做

 grep puddle2_1557936 | cut -d ":" -f1

then it will display

然后它会显示

puddle2_1557936

So is there anyway to kind of "inverse" the delimiter cut command?

那么无论如何要“反转”定界符剪切命令？

NOTE: The solution muststart off with grep puddle2_15579636.

注意：解决方案必须以grep puddle2_15579636.

回答by Gilles Quenot

You don't need to change the delimiter to display the right part of the string with cut.

您无需更改分隔符即可使用cut.

The -fswitch of the cutcommand is the n-TH element separated by your delimiter : :, so you can just type :

命令的-f开关cut是由分隔符 : 分隔的 n-TH 元素:，因此您只需键入：

 grep puddle2_1557936 | cut -d ":" -f2

---

---

Another solutions (adapt it a bit) if you want fun :

如果您想玩得开心，另一种解决方案（稍微调整一下）：

Using grep:

使用grep：

grep -oP 'puddle2_1557936:\K.*' <<< 'puddle2_1557936:/home/rogers.williams/folderz/puddle2'                                                                        
/home/rogers.williams/folderz/puddle2

or still with look aroundregex

或者仍然环顾正则表达式

grep -oP '(?<=puddle2_1557936:).*' <<< 'puddle2_1557936:/home/rogers.williams/folderz/puddle2'                                                                    
/home/rogers.williams/folderz/puddle2

or with perl:

或使用perl：

perl -lne '/puddle2_1557936:(.*)/ and print ' <<< 'puddle2_1557936:/home/rogers.williams/folderz/puddle2'                                                      
/home/rogers.williams/folderz/puddle2

or using ruby(thanks to glenn Hymanman)

或使用ruby（感谢glenn Hymanman）

ruby -F: -ane '/puddle2_1557936/ and puts $F[1]' <<< 'puddle2_1557936:/home/rogers.williams/folderz/puddle2'
/home/rogers.williams/folderz/puddle2

or with awk:

或使用awk：

awk -F'puddle2_1557936:' '{print }'  <<< 'puddle2_1557936:/home/rogers.williams/folderz/puddle2'
/home/rogers.williams/folderz/puddle2

or with python:

或使用python：

python -c 'import sys; print(sys.argv[1].split("puddle2_1557936:")[1])' 'puddle2_1557936:/home/rogers.williams/folderz/puddle2'
/home/rogers.williams/folderz/puddle2

or using only bash:

或仅使用bash：

IFS=: read _ a <<< "puddle2_1557936:/home/rogers.williams/folderz/puddle2"
echo "$a"
/home/rogers.williams/folderz/puddle2

or using jsin a shell:

或在shell 中使用js：

js<<EOF
var x = 'puddle2_1557936:/home/rogers.williams/folderz/puddle2'
print(x.substr(x.indexOf(":")+1))
EOF
/home/rogers.williams/folderz/puddle2

or using phpin a shell:

或在shell 中使用php：

php -r 'preg_match("/puddle2_1557936:(.*)/", $argv[1], $m); echo "$m[1]\n";' 'puddle2_1557936:/home/rogers.williams/folderz/puddle2' 
/home/rogers.williams/folderz/puddle2