从另一个脚本调用一个 Bash 脚本并传递带引号和空格的参数
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Calling one Bash script from another Script passing it arguments with quotes and spaces
提问by nmadhok
I made two test bash scripts on Linux to make the problem clear.
我在 Linux 上做了两个测试 bash 脚本来明确问题。
TestScript1 looks like:TestScript1 看起来像： echo "TestScript1 Arguments:"
echo ""
echo ""
echo "$#"
./testscript2
echo "TestScript2 Arguments received from TestScript1:"
echo ""
echo ""
echo "$#"
./testscript1 "Firstname Lastname" [email protected]
TestScript1 Arguments:
Firstname Lastname
[email protected]
2
TestScript2 Arguments received from TestScript1:
Firstname Lastname
[email protected]
2
TestScript1 Arguments:
Firstname Lastname
[email protected]
2
TestScript2 Arguments received from TestScript1:
Firstname
Lastname
3
How do i solve this problem? I want to get the desired output instead of the actual output.
我该如何解决这个问题？我想获得所需的输出而不是实际输出。
采纳答案by Markku K.
Quote your args in Testscript 1:
在 Testscript 1 中引用您的参数：
echo "TestScript1 Arguments:"
echo ""
echo ""
echo "$#"
./testscript2 "" ""
回答by Olivier Dulac
You need to use : "$@"(WITH the quotes) or "${@}"(same, but also telling the shell where the variable name starts and ends).
您需要使用 :（"$@"带引号）或"${@}"（相同，但也要告诉 shell 变量名的开始和结束位置）。
(and do NOT use : $@, or "$*", or $*).
（并且不要使用 : $@, or "$*", or $*）。
ex:
前任：
#testscript1:
echo "TestScript1 Arguments:"
for an_arg in "$@" ; do
echo "${an_arg}"
done
echo "nb of args: $#"
./testscript2 "$@" #invokes testscript2 with the same arguments we received
I'm not sure I understood your other requirement ( you want to invoke './testscript2' in single quotes?) so here are 2 wild guesses (changing the last line above) :
我不确定我是否理解您的其他要求（您想在单引号中调用 './testscript2'？）所以这里有 2 个大胆的猜测（更改上面的最后一行）：
'./testscript2' "$@" #only makes sense if "/path/to/testscript2" containes spaces?
./testscript2 '"some thing" "another"' "$var" "$var2" #3 args to testscript2
Please give me the exact thing you are trying to do
请给我你正在尝试做的确切的事情
edit: after his comment saying he attempts tesscript1 "$1" "$2" "$3" "$4" "$5" "$6" to run : salt 'remote host' cmd.run './testscript2 $1 $2 $3 $4 $5 $6'
编辑：在他的评论说他尝试 tesscript1 "$1" "$2" "$3" "$4" "$5" "$6" 运行后： salt 'remote host' cmd.run './testscript2 $1 $2 $3 $4 $5 $6'
You have many levels of intermediate: testscript1 on host 1, needs to run "salt", and give it a string launching "testscrit2" with arguments in quotes...
您有许多中间级别：主机 1 上的 testscript1，需要运行“salt”，并给它一个字符串，启动“testscrit2”，参数用引号...
You could maybe "simplify" by having:
您可以通过以下方式“简化”：
#testscript1
#we receive args, we generate a custom script simulating 'testscript2 "$@"'
theargs="''"
shift
for i in "$@" ; do
theargs="${theargs} '$i'"
done
salt 'remote host' cmd.run "./testscript2 ${theargs}"
if THAt doesn't work, then instead of running "testscript2 ${theargs}", replace THE LAST LINE above by
如果这不起作用，那么不要运行“testscript2 ${theargs}”，而是将上面的最后一行替换为
echo "./testscript2 ${theargs}" >/tmp/runtestscript2.$$ #generate custom script locally ($$ is current pid in bash/sh/...)
scp /tmp/runtestscript2.$$ user@remotehost:/tmp/runtestscript2.$$ #copy it to remotehost
salt 'remotehost' cmd.run "./runtestscript2.$$" #the args are inside the custom script!
ssh user@remotehost "rm /tmp/runtestscript2.$$" #delete the remote one
rm /tmp/runtestscript2.$$ #and the local one
回答by Linsong Guo
I found following program works for me
我发现以下程序对我有用
test1.sh
a=xxx
test2.sh $a
in test2.sh you use $1to refer variable ain test1.sh
在 test2.sh 中，您$1用来引用atest1.sh 中的变量
echo $1
回声 $1
The output would be xxx
输出将是 xxx
