bash grep在bash中获取匹配文本的文件名和行号
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grep get matched text's filename and line number in bash
提问by Kyle Decot
I want to do a grepin bash on a folder searching for the term foobar. I then want to output all of the matches along w/ the filenameand line numberwhere the occurrences were found. Is this possible?
我想grep在搜索术语的文件夹上执行in bash foobar。然后我想输出所有匹配的文件名和找到出现的行号。这可能吗？
I need the output to look like:
我需要输出看起来像：
{{filename}}:{{line_number}} - {{matched_text}}
回答by Paused until further notice.
grep -nrH 'regex' /dir/
-His the option that adds filenames, -nadds line numbers, -ris recursive
-H是添加文件名、-n添加行号的选项，-r是递归的
I get filenames even without the -Hunless there's only one file.
即使没有文件名，我也会得到文件名，-H除非只有一个文件。
Add -ifor case-insensitive
添加-i不区分大小写
Add -Efor extended regular expressions
添加-E扩展正则表达式
回答by mamills
Use the -n or --line-number option
使用 -n 或 --line-number 选项
grep -n foobar
回答by Zac B
Yes; try:
grep -nr "expression" /path/to/files/
是的; 尝试：
grep -nr "expression" /path/to/files/
回答by Prince John Wesley
awkbased solution:
awk基于解决方案：
awk '/REGEX/{print FILENAME":"FNR" - "find PATH-TO-START -type f -exec awk '/REGEX/{print FILENAME":"FNR" - "##代码##}' {} \;
}' PATH
For a recursive path search,
对于递归路径搜索，
##代码##