C++ 为什么这个编译器错误?- 没有匹配的函数调用'std::basic_ofstream<char>::open(std::string&)'

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时间:2020-08-28 21:00:24  来源:igfitidea点击:

why this compiler error? - no matching function for call to 'std::basic_ofstream<char>::open(std::string&)'

c++gcc

提问by beauxq

This works on Visual Studio and it works on GCC 4.9.2 on one computer.

这适用于 Visual Studio,适用于一台计算机上的 GCC 4.9.2。

But on a different computer, I think it's the same GCC 4.9.2 compiler, but it gives me this error.

但是在另一台计算机上,我认为它是相同的 GCC 4.9.2 编译器,但它给了我这个错误。

Am I missing something? What's going on?

我错过了什么吗?这是怎么回事?

#include <iostream>
#include <fstream>
#include <string>

using namespace std;

int main()
{
    string filename;
    filename = "teststring";
    ofstream fout;
    fout.open(filename);
    fout << "Hello world!" << endl;
    fout.close();
    return 0;
}

.

.

||=== Build: Debug in fileiotest (compiler: TDM32 GNU GCC Compiler 4.9.2 dw2) ===|
F:\Users\XXX\cpp\fileiotest\main.cpp||In function 'int main()':|
F:\Users\XXX\cpp\fileiotest\main.cpp|12|error: no matching function for call to 'std::basic_ofstream<char>::open(std::string&)'|
F:\Users\XXX\cpp\fileiotest\main.cpp|12|note: candidate is:|
F:\TDM-GCC-32\lib\gcc\mingw32.9.2-dw2\include\c++\fstream|716|note: void std::basic_ofstream<_CharT, _Traits>::open(const char*, std::ios_base::openmode) [with _CharT = char; _Traits = std::char_traits<char>; std::ios_base::openmode = std::_Ios_Openmode]|
F:\TDM-GCC-32\lib\gcc\mingw32.9.2-dw2\include\c++\fstream|716|note:   no known conversion for argument 1 from 'std::string {aka std::basic_string<char>}' to 'const char*'|
||=== Build failed: 1 error(s), 0 warning(s) (0 minute(s), 0 second(s)) ===|

回答by Lightness Races in Orbit

This overload's new in C++11, which means you need to pass -std=c++11in the build command.

此重载是 C++11 中的新内容,这意味着您需要传入-std=c++11build 命令。

In C++03, we used to write this:

在 C++03 中,我们曾经这样写:

fout.open(filename.c_str());