从 MVC 控制器返回 Json 数据
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Returning Json data from MVC controller
提问by user557211
public ActionResult About()
{
List<Stores> listStores = new List<Stores>();
listStores = this.GetResults("param");
return Json(listStores, "Stores", JsonRequestBehavior.AllowGet);
}
Using the above code I am able to get the below result
使用上面的代码我可以得到下面的结果
[{"id":"1","name":"Store1","cust_name":"custname1","telephone":"1233455555","email":"[email protected]","geo":{"latitude":"12.9876","longitude":"122.376237"}},
{"id":"2","name":"Store2","cust_name":"custname2","telephone":"1556454","email":"[email protected]","geo":{"latitude":"12.9876","longitude":"122.376237"}},
How would I able to get the result in below format?
我怎样才能得到以下格式的结果？
{
"stores" : [
{"id":"1","name":"Store1","cust_name":"custname1","telephone":"1233455555","email":"[email protected]",
"geo":{"latitude":"12.9876","longitude":"122.376237"}},
{"id":"2","name":"Store2","cust_name":"custname2","telephone":"1556454","email":"[email protected]","geo":{"latitude":"12.9876","longitude":"122.376237"}} ]
}
I would like to have the storesat the beginning of the data.
我想stores在数据的开头。
Please help me in this regard.
请在这方面帮助我。
回答by Rich O'Kelly
You will need to create an object that contains the stores within a property named stores:
您将需要创建一个对象，该对象包含名为 stores 的属性中的商店：
public ActionResult About()
{
var result = new { stores = this.GetResults("param") };
return Json(result, "Stores", JsonRequestBehavior.AllowGet);
}
I've used an anonymous type for simplicity here, if this result type were required in multiple places you may consider creating a 'proper' class for it.
为简单起见，我在这里使用了匿名类型，如果在多个地方需要这种结果类型，您可以考虑为它创建一个“适当的”类。
回答by Tx3
JavaScriptSerializercan be found from namespace System.Web.Script.Serialization
JavaScriptSerializer可以从命名空间中找到 System.Web.Script.Serialization
var ser = new JavaScriptSerializer();
var jsonStores = ser.Serialize(stores);
return Json(new { stores: jsonStores }, "Stores", JsonRequestBehavior.AllowGet);
回答by Karan Singh
if you want to send object to client side as Json format like Data-table,List,Dictionary etc. then need to override jsonResult and ExecuteResult
如果您想将对象以 Json 格式（如 Data-table、List、Dictionary 等）发送到客户端，则需要覆盖 jsonResult 和 ExecuteResult
other wise use linq format to return data like
其他明智的使用 linq 格式返回数据，如
using JSON.NET(must need to use override jsonResult and ExecuteResult )
使用 JSON.NET（必须使用覆盖 jsonResult 和 ExecuteResult ）
DataTable dt = new DataTable();//some data in table
return json("data",JsonConvert.SerializeObject(dt))
other option using linq
使用 linq 的其他选项
var Qry = (from d in dt.AsEnumerable()
select new
{
value = d.Field<int>("appSearchID"),
text = d.Field<string>("appSaveSearchName"),
type = d.Field<int>("appSearchTypeStatus")
});
return json("Data", Qry);
override methods
覆盖方法
protected override JsonResult Json(object data, string contentType, Encoding contentEncoding, JsonRequestBehavior behavior)
{
try
{
return new JsonNetResult
{
Data = data,
ContentType = contentType,
ContentEncoding = contentEncoding,
JsonRequestBehavior = behavior,
MaxJsonLength = int.MaxValue
};
}
catch (Exception)
{
throw;
}
}
public class JsonNetResult : JsonResult
{
public override void ExecuteResult(ControllerContext context)
{
try
{
HttpResponseBase response = context.HttpContext.Response;
response.ContentType = string.IsNullOrEmpty(this.ContentType) ? "application/json" : this.ContentType;
if (this.ContentEncoding != null)
response.ContentEncoding = this.ContentEncoding;
if (this.Data == null)
return;
using (StringWriter sw = new StringWriter())
{
response.Write(this.Data);
}
}
catch (Exception)
{
throw;
}
}
}
回答by Tr1stan
public class StoresViewModel{
public List<Stores> stores {get;set;}
}
public ActionResult About()
{
List<Stores> listStores = new List<Stores>();
listStores = this.GetResults("param");
StoresViewModelmodel = new StoresViewModel(){
stores = listStores;
}
return Json(model, JsonRequestBehavior.AllowGet);
}
