Python 更改 value_counts 中的排序
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changing sort in value_counts
提问by Mark Ginsburg
If I do
如果我做
mt = mobile.PattLen.value_counts() # sort True by default
I get
我得到
4 2831
3 2555
5 1561
[...]
If I do
如果我做
mt = mobile.PattLen.value_counts(sort=False)
I get
我得到
8 225
9 120
2 1234
[...]
What I am trying to do is get the output in 2, 3, 4 ascending order (the left numeric column). Can I change value_counts somehow or do I need to use a different function.
我想要做的是按 2、3、4 升序（左侧数字列）获取输出。我可以以某种方式更改 value_counts 还是需要使用不同的函数。
回答by jezrael
I think you need sort_index, because the left column is called index. The full command would be mt = mobile.PattLen.value_counts().sort_index(). For example:
我认为你需要sort_index，因为左边的列被称为index. 完整的命令是mt = mobile.PattLen.value_counts().sort_index(). 例如：
mobile = pd.DataFrame({'PattLen':[1,1,2,6,6,7,7,7,7,8]})
print (mobile)
PattLen
0 1
1 1
2 2
3 6
4 6
5 7
6 7
7 7
8 7
9 8
print (mobile.PattLen.value_counts())
7 4
6 2
1 2
8 1
2 1
Name: PattLen, dtype: int64
mt = mobile.PattLen.value_counts().sort_index()
print (mt)
1 2
2 1
6 2
7 4
8 1
Name: PattLen, dtype: int64
