jQuery 使用 .post() 处理错误
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error handling with .post()
提问by meo
I have to modify a project written by someone else. Because the code is a mess I can't really change this $.post() (or replace it by $.ajax()). What I need to do, is to know if the post returns something else then JSON and return it.
我必须修改别人写的项目。因为代码一团糟，我无法真正更改此 $.post()（或将其替换为 $.ajax()）。我需要做的是知道帖子是否返回其他内容然后返回 JSON 并返回它。
$.post('balbal.html', json, function(data) { ... my coude ... }, 'json')
I can see the post response in the console.log. Is there a simple way to retrieve it?
我可以在 console.log 中看到帖子响应。有没有简单的方法来找回它？
采纳答案by Phil.Wheeler
There's a couple of ways to do it, but if you're not getting the error response available through the returned JSON data object, you can use $.ajaxSetup()to define defaults for allajax calls through jQuery. Even though the $.post()method doesn't specify an error handler or callback in and of itself, the $.ajaxSetup()method will capture any ajax faults and execute the function you define for it.
有几种方法可以做到这一点，但是如果您没有通过返回的 JSON 数据对象获得可用的错误响应，您可以使用$.ajaxSetup()通过 jQuery为所有ajax 调用定义默认值。即使该$.post()方法本身没有指定错误处理程序或回调，该$.ajaxSetup()方法也会捕获任何 ajax 错误并执行您为其定义的函数。
Alternatively, there is also an $.ajaxError()function that will do the same sort of thing.
或者，还有一个$.ajaxError()函数可以做同样的事情。
Note that this will not work if your JSON response is returned correctly but with a server-side error code. If you want to capture these sorts of cases, you might be best to look for them using the $.ajaxComplete()method
请注意，如果您的 JSON 响应正确返回但带有服务器端错误代码，这将不起作用。如果您想捕获这些类型的情况，最好使用$.ajaxComplete()方法查找它们
回答by hyprnick
Define the error callback immediately after the post. Note the semi-colon placement only at the end.
发布后立即定义错误回调。请注意分号位置仅在末尾。
$.post('balbal.html', json, function(data) {
// ... my code ...
})
.fail(function(response) {
alert('Error: ' + response.responseText);
});
http://api.jquery.com/deferred.fail/
http://api.jquery.com/deferred.fail/
For older versions of jQuery (pre-1.8)Use .errorinstead with the same syntax.
对于旧版本的 jQuery（1.8 之前），请使用.error代替相同的语法。
回答by Victor
You can use $.ajax()($.postis a shortcut that ends up calling it anyway), and define the error callback.
您可以使用$.ajax()($.post是最终调用它的快捷方式)，并定义错误回调。
Or, if you really do not want to do that, call
或者，如果您真的不想这样做，请致电
$.ajaxError(function(){
//error handler
})
before that $.post
在那之前 $.post
