日志文件中两个日期之间的 Bash Grep 行
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/31470843/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Bash Grep lines between 2 dates in log file
提问by ramana_k
I have a log file that looks like this:
我有一个看起来像这样的日志文件：
2015-07-07 11:23:33,006 DEBUG : Invoking handleMessage on interceptor org.apache.cxf.interceptor.LoggingInInterceptor@2798240a
name="New Test User"
domicile="A Place"
name="Test User"
2015-07-07 15:00:33,008 DEBUG : Invoking handleMessage on interceptor org.apache.cxf.interceptor.
Now i call my bash script with a paramter like this:
现在我用这样的参数调用我的 bash 脚本：
./test.sh -t 2015-07-07,11:00-2015-07-08,20:00.
So my question is: How can i get the text between the two dates in the log file if i use my time range like 2015-07-07 11:00 until 2015-07-08 20:00?
所以我的问题是：如果我使用像 2015-07-07 11:00 到 2015-07-08 20:00 这样的时间范围，我如何获得日志文件中两个日期之间的文本？
Thanks
谢谢
采纳答案by ramana_k
I have written a test script, that works for me
我写了一个测试脚本，这对我有用
#!/bin/bash
startDate=$(echo | cut -d "-" -f 1 | cut -d "," -f 1)
endDate=$(echo | cut -d "-" -f 2 | cut -d "," -f 1)
startTime=$(echo | cut -d "-" -f 1 | cut -d "," -f 2)
endTime=$(echo | cut -d "-" -f 2 | cut -d "," -f 2)
#Script Parameter Format to search in Log Files: DD.MM.YYYY,hh:mm-DD.MM.YYYY,hh:mm
timestampStart=$(echo $startDate | cut -d "." -f 3)-$(echo $startDate | cut -d "." -f 2)-$(echo $startDate | cut -d "." -f 1)" "$startTime
timestampEnd=$(echo $endDate | cut -d "." -f 3)-$(echo $endDate | cut -d "." -f 2)-$(echo $endDate | cut -d "." -f 1)" "$endTime
tStart=`date --date="$timestampStart" +%s`
tEnd=`date --date="$timestampEnd" +%s`
while read line; do
re="[0-9]{4}-[0-9]{2}-[0-9]{2} [0-9]{2}:[0-9]{2}:[0-9]{2},[0-9]{3}"
if [[ $line =~ $re ]]; then
searchDate=$(echo $line | cut -d "," -f 1)
tSearch=`date --date="$searchDate" +%s`
fi
if [ $tSearch -ge $tStart ] && [ $tSearch -lt $tEnd ];then
echo $line
fi
done < logs/backup/log/my_test.log
and i can execute it like this:
我可以像这样执行它：
./test.sh -t 07.07.2015,12:48:32-07.07.2015,13:01
回答by Fiximan
sed -n "/2015-07-07 11:23:33/,/2015-07-07 15:00:33/p"
or more general:
或更一般的：
sed -n "/$START/,/$END/p"
回答by ramana_k
You can use Perl range operator for this. I am assuming that the log file is sorted by date. Another assumption is that dates are in the format YYYY-MM-DD.
您可以为此使用 Perl 范围运算符。我假设日志文件按日期排序。另一个假设是日期的格式为 YYYY-MM-DD。
cat logfile | perl -ne 'print if (/2015-07-07 11:00/ .. /2015-07-08 20:00/)'
