java Hibernate 映射异常 - 无法确定以下类型的类型：
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Hibernate mapping exception - Could not determine type for:
提问by Fabio K
Im trying to configure my entities but hibernate throws the following exception:
我正在尝试配置我的实体，但休眠会引发以下异常：
org.hibernate.MappingException: Could not determine type for: com.sd.entity.SDUserProductAcess, at table: SDUser, for columns: [org.hibernate.mapping.Column(productAccess)]
[PersistEngine] Failed to initialize persistence engine!java.lang.NullPointerException
These are my Entities:
这些是我的实体：
@Entity
@Inheritance(strategy = InheritanceType.JOINED)
public class SDObject
{
@Id
@GeneratedValue
private long sdId;
private String sdType;
public long getSdId()
{
return sdId;
}
public void setSdId(long sdId)
{
this.sdId = sdId;
}
public String getSdType()
{
return sdType;
}
public void setSdType(String sdType)
{
this.sdType = sdType;
}
}
The next one:
下一个：
@Entity
public class SDUser extends SDObject
{
@Column(unique = true)
private String code;
private String password;
private SDUserProductAcess productAccess;
public String getCode()
{
return code;
}
public void setCode(String code)
{
this.code = code;
}
public String getPassword()
{
return password;
}
public void setPassword(String password)
{
this.password = password;
}
@OneToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY)
public SDUserProductAcess getProductAccess()
{
return productAccess;
}
public void setProductAccess(SDUserProductAcess productAccess)
{
this.productAccess = productAccess;
}
The last one:
最后一个：
@Entity
public class SDUserProductAcess extends SDObject
{
private boolean adm;
public boolean isAdm()
{
return adm;
}
public void setAdm(boolean adm)
{
this.adm = adm;
}
}
Hibernate can't determine the type for column productAccess, located in SDUser entity. I'm new to Hibernate and I can't figure out what is happening.
Hibernate 无法确定位于 SDUser 实体中的列 productAccess 的类型。我是 Hibernate 的新手，我无法弄清楚发生了什么。
Should I provide some kind of ID?
我应该提供某种身明吗？
Thanks!!
谢谢！！
回答by Vlad Mihalcea
In SDUseryou need to add the association info on the SDUserAccess:
在SDUser您需要添加的关联信息SDUserAccess：
@ManyToOne
@JoinColumn(name = "sdId")
private SDUserProductAcess productAccess;
