Python 递减循环

Question

提问by pandoragami

I want to have a for loop like so:

我想要一个像这样的 for 循环：

for counter in range(10,0):
       print counter,

and the output should be 10 9 8 7 6 5 4 3 2 1

并且输出应该是 10 9 8 7 6 5 4 3 2 1

Answer 1

a = " ".join(str(i) for i in range(10, 0, -1))
print (a)

Answer 2

Check out the rangedocumentation, you have to define a negative step:

查看range文档，您必须定义一个否定步骤：

>>> range(10, 0, -1)
[10, 9, 8, 7, 6, 5, 4, 3, 2, 1]

Answer 3

You need to give the range a -1 step

你需要给范围一个 -1 步

 for i in range(10,0,-1):
    print i

Answer 4

range step should be -1

范围步长应为 -1

   for k in range(10,0,-1):
      print k

Answer 5

for i in range(10,0,-1):
    print i,

The range() function will include the first value and exclude the second.

range() 函数将包含第一个值并排除第二个值。