在 bash 中为备用输出行着色的简单方法
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Simple way to colour alternate output lines in bash
提问by naught101
I have need to grep an entire directory for a string, and I get about 50 results. I would like to colour each second line, either text colour or background colour. Best would be a script that I can pipe the output of any command to, and so that it spits out the same (albeit coloured) output.
我需要为一个字符串 grep 整个目录，我得到大约 50 个结果。我想为每一行着色，文本颜色或背景颜色。最好是一个脚本，我可以将任何命令的输出通过管道传输到它，这样它就可以输出相同的（尽管是彩色的）输出。
回答by Kimvais
Not very pretty but does the trick:
不是很漂亮，但有诀窍：
(save this to foo.bashand do grep whatever wherever | ./foo.bash)
（保存foo.bash并执行grep whatever wherever | ./foo.bash）
#!/bin/bash
while read line
do
echo -e "\e[1;31m$line"
read line
echo -e "\e[1;32m$line"
done
echo -en "\e[0m"
Here you can find the list of color codes in bash.
在这里您可以找到bash 中的颜色代码列表。
回答by JasonSmith
Perl is installed on many systems. You could have it alternate for you:
Perl 安装在许多系统上。你可以让它为你替代：
grep -r whatever somedir/ | perl -pe '$_ = "3[1;29m$_3[0m" if($. % 2)'
In Perl $.can be substituted with $INPUT_LINE_NUMBERif you prefer readability.
如果您更喜欢可读性，在 Perl$.中可以替换为$INPUT_LINE_NUMBER。
回答by Kimvais
and here is the same in python;
这在python中也是一样的；
import sys
for line_number,line in enumerate(sys.stdin.readlines()):
print '%s[1;3%dm%s%s[0m' % (chr(27),(line_number % 2+1),line,chr(27)),
回答by pixelbeat
This is to delineate wrapped lines I presume? This shell script uses a background color from the 256 colorpalette, so as not to interfere with other highlighting that grep --color might do.
这是为了描绘我认为的包裹线？此 shell 脚本使用256 色调色板中的背景颜色，以免干扰 grep --color 可能执行的其他突出显示。
#!/bin/sh
c=0
while read line; do
[ $(($c%2)) -eq 1 ] && printf "3[48;5;60m"
printf "%s3[0m\n" "$line"
c=$(($c+1))
done
This has the caveat that backslashes etc. within the line will be mangled, so treat this as pseudo code for reimplementation
这有一个警告，即行内的反斜杠等将被破坏，因此将其视为重新实现的伪代码
