java 运行主类时 org.apache.openjpa.persistence.ArgumentException
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org.apache.openjpa.persistence.ArgumentException while running the main class
提问by Sarbong
I using using maven simple java project
我使用使用 maven 简单的 java 项目
Im getting the following exception while running the main class
我在运行主类时收到以下异常
346 INFO [main] openjpa.Runtime - OpenJPA dynamically loaded the class
enhancer. Any classes that were not enhanced at build time
will be enhanced when they are loaded by the JVM.
414 INFO [main] openjpa.Runtime - Starting OpenJPA 2.3.0
<openjpa-2.3.0-r422266:1540826 fatal user error>
org.apache.openjpa.persistence.ArgumentException: The persistence provider is
attempting to use properties in the persistence.xml file to resolve the data
source. A Java Database Connectivity (JDBC) driver or data source class name
must be specified in the openjpa.ConnectionDriverName or
javax.persistence.jdbc.driver property. The following properties are available
in the configuration: "org.apache.openjpa.jdbc.conf.JDBCConfigurationImpl@442ce698".
at org.apache.openjpa.jdbc.schema.DataSourceFactory.newDataSource(DataSourceFactory.java:72)
at org.apache.openjpa.jdbc.conf.JDBCConfigurationImpl.createConnectionFactory(JDBCConfigurationImpl.java:849)
at org.apache.openjpa.jdbc.conf.JDBCConfigurationImpl.getDBDictionaryInstance(JDBCConfigurationImpl.java:602)
at org.apache.openjpa.jdbc.meta.MappingRepository.endConfiguration(MappingRepository.java:1518)
at org.apache.openjpa.lib.conf.Configurations.configureInstance(Configurations.java:535)
at org.apache.openjpa.lib.conf.Configurations.configureInstance(Configurations.java:460)
at org.apache.openjpa.lib.conf.PluginValue.instantiate(PluginValue.java:121)
at org.apache.openjpa.conf.MetaDataRepositoryValue.instantiate(MetaDataRepositoryValue.java:68)
at org.apache.openjpa.lib.conf.ObjectValue.instantiate(ObjectValue.java:83)
at org.apache.openjpa.conf.OpenJPAConfigurationImpl.newMetaDataRepositoryInstance(OpenJPAConfigurationImpl.java:967)
at org.apache.openjpa.conf.OpenJPAConfigurationImpl.getMetaDataRepositoryInstance(OpenJPAConfigurationImpl.java:958)
at org.apache.openjpa.kernel.AbstractBrokerFactory.makeReadOnly(AbstractBrokerFactory.java:643)
at org.apache.openjpa.kernel.AbstractBrokerFactory.newBroker(AbstractBrokerFactory.java:203)
at org.apache.openjpa.kernel.DelegatingBrokerFactory.newBroker(DelegatingBrokerFactory.java:155)
at org.apache.openjpa.persistence.EntityManagerFactoryImpl.createEntityManager(EntityManagerFactoryImpl.java:226)
at org.apache.openjpa.persistence.EntityManagerFactoryImpl.createEntityManager(EntityManagerFactoryImpl.java:153)
at org.apache.openjpa.persistence.EntityManagerFactoryImpl.createEntityManager(EntityManagerFactoryImpl.java:59)
at org.msharma.JpaImpl.main(JpaImpl.java:15)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:601)
at com.intellij.rt.execution.application.AppMain.main(AppMain.java:134)
My entity clas
我的实体类
@Entity(name ="customer")
public class Customer implements Serializable{
@Id
@Column(name ="cust_id", nullable = false)
@GeneratedValue(strategy = GenerationType.AUTO)
private long custId;
@Column(name = "first_name",length = 50, nullable = false)
private String firstName;
@Column(name = "last_name",length = 50)
private String lastName;
// By default column name is same as attribute name
private String street;
private String appt;
private String city;
@Column(name = "zip_code",length = 50, nullable = false)
private String zipCode;
@Column(name = "cust_type",length = 50, nullable = false)
private String custType;
@Version
@Column(name = "last_updated_time")
private Date updatedTime;
public Customer(){}
// getters and setters
}
This is my persistence.xml
这是我的persistence.xml
<?xml version="1.0"?>
<persistence version="2.0" xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence
http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="testjpa" transaction-type="RESOURCE_LOCAL">
<provider>
org.apache.openjpa.persistence.PersistenceProviderImpl
</provider>
<class>org.somepack.Customer</class>
<properties>
<property name="openjpa.ConnectionURL"
value="jdbc:mysql://localhost:3306/test"/>
<property name="openjpa.ConnectionDriverName"
value="com.mysql.jdbc.Driver"/>
<property name="openjpa.ConnectionUserName" value="root"/>
<property name="openjpa.ConnectionPassword" value="pass"/>
<property name="openjpa.Log" value="SQL=TRACE"/>
</properties>
</persistence-unit>
</persistence>
This is my mainClass
这是我的 mainClass
public static void main(String[] args) {
try {
EntityManagerFactory entityManagerFactory = Persistence
.createEntityManagerFactory("testjpa");
EntityManager entityManager = entityManagerFactory.createEntityManager();
EntityTransaction entityTransaction = entityManager.getTransaction();
entityTransaction.begin();
Customer customer = new Customer();
//set the properties to the customer object
entityManager.persist(customer);
entityTransaction.commit();
entityManager.close();
entityManagerFactory.close();
}
catch (Exception e){
e.printStackTrace();
}
}
How do I resolve the problem .
我该如何解决这个问题。
I have openjpa, openjpa-persistence-jdbc, mysql-connector-java dependencies in my POM.xml
我的 POM.xml 中有 openjpa、openjpa-persistence-jdbc、mysql-connector-java 依赖项
and my persistence.xmlis under src/main/resources
我persistence.xml的在下src/main/resources
回答by SparkOn
As you said your persistence.xml is under src/main/resourcesso may be it is unable to read it
正如您所说，您的persistence.xml 在下，src/main/resources因此可能无法读取它
you must place it under src/main/resources/META-INF
你必须把它放在 src/main/resources/META-INF
One more thing add
补充一件事
<property name="openjpa.jdbc.SynchronizeMappings" value="buildSchema(ForeignKeys=true)"/>
to your persistence.xml.
到您的persistence.xml。
If you add the openjpa.jdbc.SynchronizeMappingsproperty as shown below OpenJPA will auto-create all your tables, all your primary keys and all foreign keys exactly to match your objects
如果您添加openjpa.jdbc.SynchronizeMappings如下所示的属性，OpenJPA 将自动创建您的所有表、所有主键和所有外键以完全匹配您的对象
回答by Dmytro Plekhotkin
Add <property name="javax.persistence.jdbc.driver" value="com.mysql.jdbc.Driver" />to your persistence.xml:
添加<property name="javax.persistence.jdbc.driver" value="com.mysql.jdbc.Driver" />到您的persistence.xml：
<?xml version="1.0"?>
<persistence version="2.0" xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence
http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="testjpa" transaction-type="RESOURCE_LOCAL">
<provider>
org.apache.openjpa.persistence.PersistenceProviderImpl
</provider>
<class>org.somepack.Customer</class>
<properties>
<property name="openjpa.ConnectionURL"
value="jdbc:mysql://localhost:3306/test"/>
<property name="openjpa.ConnectionDriverName"
value="com.mysql.jdbc.Driver"/>
<property name="openjpa.ConnectionUserName" value="root"/>
<property name="openjpa.ConnectionPassword" value="pass"/>
<property name="openjpa.Log" value="SQL=TRACE"/>
<property name="javax.persistence.jdbc.driver" value="com.mysql.jdbc.Driver" />
</properties>
</persistence-unit>
</persistence>
