Laravel 4，查看带参数的composer？
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时间：2020-09-14 07:44:08 来源:igfitidea点击:
Laravel 4, view composer with parameters?
提问by user2094178
Suppose I have this:
假设我有这个：
//controllers/BlogController.php
$data["post"] = $post = Blog::recent_post();
$data["posts_related"] = Blog::posts_related($post->category_id,5);
return View::make('blog.home', $data);
//views/sidebars/related.blade.php
@foreach($posts_related as $r)
<p>{{ $r->name }}</p>
@endforeach
//views/blog/home.blade.php
@include('sidebars.related')
My question is, how could I transfer:
我的问题是，我怎么能转移：
$data["posts_related"] = Blog::posts_related($post->category_id,5);
To a view composer, since it seems I can't pass parameters to a view composer, but I can't be sure.
对于视图作曲家，因为我似乎无法将参数传递给视图作曲家，但我不能确定。
I appreciate any help!
我感谢任何帮助！
回答by Yahia Reyhani
In View Composer you can retrive data that passed to View.
在 View Composer 中，您可以检索传递给 View 的数据。
View::composer('sidebars.related', function($view)
{
//$data contains category_id
$viewdata= $view->getData();
//Retrive based on category_id
$posts_related = Blog::posts_related($viewdata['category_id'],5);
//pass related post to view
$view->with('posts_related', $posts_related);
});
now everywhere you can use:
现在到处都可以使用：
View::make('sidebars.related')->with(array('category_id' => 6));
