PHP 使用 str_replace 替换或删除空行的简单方法
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PHP Simple way to replace or remove empty lines with str_replace
提问by Stephayne
$line-out = str_replace('\r', '', str_replace('\n', '', $line-in));
The above works for me but, I saw a [\n\r] example somewhere and I cannot seem to find it.
以上对我有用，但是，我在某处看到了 [\n\r] 示例，但似乎找不到它。
I just want to get rid any blank lines. The above is in a foreach loop.
我只想摆脱任何空行。以上是在foreach循环中。
Thanks for teaching.
谢谢教导。
回答by Lekensteyn
You shouldn't use -in variable names ;)
你不应该-在变量名中使用;)
$line_out = preg_replace('/[\n\r]+/', '', $line_in);
$line_out = str_replace(array("\n", "\r"), '', $line_in);
Manual entries:
手动输入：
回答by codaddict
str_replacecan be passed an array as:
str_replace可以通过一个数组作为：
$line_out = str_replace(array("\r","\n"), '', $line_in);
回答by nush
This is from php.net's example #2 in str_replace(modified to suit the "environment"):
这是来自 php.net's example #2 in str_replace（修改以适应“环境”）：
<?php
// Order of replacement
$str = "Line 1\nLine 2\rLine 3\r\nLine 4\n";
$order = array("\r\n", "\n", "\r");
// Processes \r\n's first so they aren't converted twice.
$newstr = str_replace($order, '', $str);
