bash grep 计数搜索多个单词
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grep count search multiple words
提问by user775187
how do I search for lines that contain multiple words? I want an "AND" relationship. I want a total count of such lines.
如何搜索包含多个单词的行？我想要一个“AND”关系。我想要这些行的总数。
grep -c -E "tok1.*tok2" file
return 0
返回 0
回答by dolphy
To use grep specifically, you can use the OR operator to allow for both possibilities:
要专门使用 grep，您可以使用 OR 运算符来实现两种可能性：
grep -c -E "(.*tok1.*tok2.*|.*tok2.*tok1.*)" file
You can also simply grep for one token, and then pipe that to a recurring grep for another token:
您也可以简单地 grep 一个令牌，然后将其通过管道传递给另一个令牌的重复 grep：
grep "tok1" file | grep -c "tok2"
Multiple greps seem to be much faster when you start introducing a lot of tokens. You can also substitute for the egrepcommand, which is a regexp version of grep...but I avoid it for the same reason: it seems to me to take drastically longer when you introduce multiple terms into the search.
当您开始引入大量令牌时，多个 grep 似乎要快得多。您还可以替换egrep命令，它是 grep 的正则表达式版本……但我出于同样的原因避免使用它：在我看来，当您在搜索中引入多个术语时，需要花费更长的时间。
回答by glenn Hymanman
In addition to grep, there is awk:
除了grep，还有awk：
awk '/tok1/ && /tok2/ {count++} END {print count}' file
回答by frankc
egrep "tok1" file | egrep -c "tok2"
egrep "tok1" 文件 | egrep -c "tok2"
