在 while 循环中未找到 Bash 脚本命令错误
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Bash script command not found error in while loop
提问by Süleyman Orhan
I have problem and cant still handle with it. :( Here is my code
我有问题，仍然无法处理。:(这是我的代码
declare -i disk_usage_rate=$(df -h /appdata/SCT_CDR | cut -d '%' -f 1 | awk 'NR==2{print }')
while ["$disk_usage_rate" -gt 80]
do
...
...
done
I get the disk usage rate from df -h command. But in while loop I get the followig error. Btw it is bash script.
我从 df -h 命令获得磁盘使用率。但是在 while 循环中，我收到了 followig 错误。顺便说一句，它是 bash 脚本。
bash: [84: command not found
bash: [84: 找不到命令
I tried so many things but I didnt solve yet.
我尝试了很多事情，但我还没有解决。
回答by vivekyad4v
You are missing space near square brackets used in while loop such as below -
您在 while 循环中使用的方括号附近缺少空格，如下所示 -
declare -i disk_usage_rate=$(df -h /appdata/SCT_CDR | cut -d '%' -f 1 | awk 'NR==2{print }')
while [ "$disk_usage_rate" -gt 80 ]
do
...
...
done
A bit of history: this is because '[' was historically not a shell-built-in but a separate executable that received the expresson as arguments and returned a result. If you didn't surround the '[' with space, the shell would be searching $PATH for a different filename (and not find it) . – Andrew Medico Jun 24 '09 at 1:13
一点历史：这是因为 '[' 在历史上不是 shell 内置的，而是一个单独的可执行文件，它接收表达式作为参数并返回结果。如果您没有用空格将 '[' 括起来，shell 将在 $PATH 中搜索不同的文件名（而不是找到它）。– Andrew Medico 2009 年 6 月 24 日 1:13
Ref - bash shell script syntax error
参考 - bash shell 脚本语法错误
回答by romaric crailox
I see one error : add a space after '['and before ']'on your while line :
我看到一个错误：在您的 while 行'['前后添加一个空格']'：
while [ "$disk_usage_rate" -gt 80 ]
Is it better ?
这个会比较好吗 ？
