ios 在 Swift 中以编程方式制作 Segue
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Make Segue programmatically in Swift
提问by Kahsn
I have two VCs: VC1 and VC2.
In VC1, I have a finish buttonwhich I programmatically made and a result arrayI want to pass to VC2.
我有两个 VC：VC1 和 VC2。在 VC1 中，我有一个finish button我以编程方式制作的和一个result array我想传递给 VC2 的。
I know how to make Segue in Storyboard, but I cannot do that at this moment since the finish buttonis programmatically made.
我知道如何在 Storyboard 中制作 Segue，但目前我无法这样做，因为它finish button是通过编程方式制作的。
If I want to pass result array using segue, is there a way to make the segue programmatically? If this is not possible, should I just present VC2 using presentViewControllerand set a delegate to pass the result array?
如果我想使用 segue 传递结果数组，有没有办法以编程方式制作 segue？如果这是不可能的，我是否应该只使用 VC2presentViewController并设置一个委托来传递result array?
回答by dehlen
You can do it like proposed in this answer: InstantiateViewControllerWithIdentifier.
您可以按照此答案中的建议进行操作： InstantiateViewControllerWithIdentifier。
Furthermore I am providing you the code from the linked answer rewritten in Swift because the answer in the link was originally written in Objective-C.
此外，我为您提供了用 Swift 重写的链接答案中的代码，因为链接中的答案最初是用 Objective-C 编写的。
let vc = UIStoryboard(name:"Main", bundle:nil).instantiateViewController(withIdentifier: "identifier") as! SecondViewController
vc.resultsArray = self.resultsArray
EDIT:
编辑：
Since this answer draws some attention I thought I provide you with another more failsafe way. In the above answer the application will crash if the ViewControllerwith "identifier"is not of type SecondViewController. In Swift you can prevent this crash by using optional binding:
由于这个答案引起了一些注意，我想我为您提供了另一种更安全的方法。在上面的答案中，如果ViewControllerwith "identifier"不是 type ，应用程序将崩溃SecondViewController。在 Swift 中，您可以通过使用可选绑定来防止这种崩溃：
guard let vc = UIStoryboard(name:"Main", bundle:nil).instantiateViewControllerWithIdentifier("identifier") as? SecondViewController else {
print("Could not instantiate view controller with identifier of type SecondViewController")
return
}
vc.resultsArray = self.resultsArray
self.navigationController?.pushViewController(vc, animated:true)
This way the ViewControlleris pushed if it is of type SecondViewController. If can not be casted to SecondViewControllera message is printed and the application remains on the current ViewController.
这样，ViewController如果它是 type ，就会被推送SecondViewController。如果无法强制转换SecondViewController为消息，则打印并且应用程序保持在当前ViewController.
回答by creeperspeak
You can still create the segue in Interface Builder by dragging from VC1 to VC2 - just drag from/to the little yellow circle at the top of the VC. Give this segue a unique name in IB, and in your finishfunction you can call performSegueWithIdentifier:, pass in the name of your segue, and that's it. In the prepareForSeguemethod you can find out which segue is being performed by accessing segue.identifier, and if it's the segue in question you can get a pointer to segue.destinationViewControllerand pass your data on that way.
您仍然可以通过从 VC1 拖动到 VC2 在 Interface Builder 中创建转场 - 只需从/拖动到 VC 顶部的小黄色圆圈即可。在 IB 中给这个 segue 一个唯一的名称，在你的finish函数中你可以调用performSegueWithIdentifier:，传入你的 segue 的名称，就是这样。在该prepareForSegue方法中，您可以通过访问 找出正在执行哪个转场segue.identifier，如果是有问题的转场，您可以获得指向segue.destinationViewController并以这种方式传递数据的指针。
