Python 从一维列表中创建一个二维列表
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Create a 2D list out of 1D list
提问by PhoonOne
I am a bit new to Python and I want to convert a 1D list to a 2D list, given the widthand lengthof this matrix.
我对 Python 有点陌生，鉴于this的width和length，我想将一维列表转换为二维列表matrix。
Say I have a list=[0,1,2,3]and I want to make a 2 by 2matrix of this list.
假设我有一个list=[0,1,2,3]，我想制作2 by 2这个列表的矩阵。
How can I get matrix [[0,1],[2,3]]width=2, length=2 out of the list?
我怎样才能得到matrix [[0,1],[2,3]]width=2, length=2 list？
采纳答案by root
Try something like that:
尝试这样的事情：
In [53]: l = [0,1,2,3]
In [54]: def to_matrix(l, n):
...: return [l[i:i+n] for i in xrange(0, len(l), n)]
In [55]: to_matrix(l,2)
Out[55]: [[0, 1], [2, 3]]
回答by wim
I think you should use numpy, which is purpose-built for working with matrices/arrays, rather than a list of lists. That would look like this:
我认为你应该使用 numpy，它是专门为处理矩阵/数组而不是列表列表而构建的。那看起来像这样：
>>> import numpy as np
>>> list_ = [0,1,2,3]
>>> a = np.array(list_).reshape(2,2)
>>> a
array([[0, 1],
[2, 3]])
>>> a.shape
(2, 2)
Avoid calling a variable listas it shadows the built-in name.
避免调用变量，list因为它隐藏了内置名称。
回答by Manik Dhingra
NumPy's built-in reshape function can be used to do such a task.
NumPy 的内置 reshape 函数可以用来完成这样的任务。
import numpy
length = 2
width = 2
_list = [0,1,2,3]
a = numpy.reshape(a, (length, width))
numpy.shape(a)
As long as you change the values within your list, and accordingly update the values of 'length' and 'width', you shouldn't receive any error.
只要您更改列表中的值，并相应地更新“长度”和“宽度”的值，您就不会收到任何错误。
