php 使用 filter_var() 来验证日期？
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Using filter_var() to verify date?
提问by Gulbahar
I'm obviously not using filter_var()correctly. I need to check that the user has entered a valid date, in the form "dd/mm/yyyy".
我显然没有正确使用filter_var()。我需要检查用户是否输入了有效日期，格式为“dd/mm/yyyy”。
This simply returns whatever I passed as a date, while I expected it to return either the date or 0/null/FALSE in case the input string doesn't look like a date:
这只是返回我作为日期传递的任何内容，而我希望它返回日期或 0/null/FALSE，以防输入字符串看起来不像日期：
$myregex = "/\d{2}\/\d{2}\/\d{4}/";
print filter_var("bad 01/02/2012 bad",FILTER_VALIDATE_REGEXP,array("options"=>array("regexp"=> $myregex)));
If someone else uses this function to check dates, what am I doing wrong? Should I use another function to validate form fields?
如果其他人使用此功能检查日期，我做错了什么？我应该使用另一个函数来验证表单域吗？
Thank you.
谢谢你。
回答by Baba
Using regex to validate date is a bad idea .. Imagine 99/99/9999can easily be seen as a valid date .. you should checkdate
使用正则表达式来验证日期是一个坏主意..试想一下，99/99/9999可以很容易地被看作是一个有效的日期..你应该了checkdate
bool checkdate ( int $month , int $day , int $year )
Simple Usage
简单使用
$date = "01/02/0000";
$date = date_parse($date); // or date_parse_from_format("d/m/Y", $date);
if (checkdate($date['month'], $date['day'], $date['year'])) {
// Valid Date
}
回答by deceze
$myregex = '~^\d{2}/\d{2}/\d{4}$~';
The regex matched because you just require that pattern anywherein the string. What you want is onlythat pattern and nothing else. So add ^and $.
正则表达式匹配，因为您只需要在字符串中的任何位置使用该模式。你想要的只是那个模式，没有别的。所以添加^和$。
Note that this still doesn't mean the value is a valid date. 99/99/9999will pass that test. I'd use:
请注意，这仍然并不意味着该值是一个有效的 date。99/99/9999将通过该测试。我会用：
if (!DateTime::createFromFormat('d/m/Y', $string))
回答by Tim
Why using a heavy RegEx, while there is a native DateTimePHP-class?
为什么使用繁重的 RegEx，而有一个原生的DateTimePHP 类？
$value = 'badbadbad';
try {
$datetime = new \DateTime($value);
$value = $datetime->format('Y-m-d');
} catch(\Exception $e) {
// Invalid date
}
Always returns the format you were expecting, if a valid datetime string was inserted.
如果插入了有效的日期时间字符串，则始终返回您期望的格式。
回答by Cmyker
回答by Benjamin Paap
Try setting the start and end for your regex like this:
尝试像这样设置正则表达式的开始和结束：
$myregex = "/^\d{2}\/\d{2}\/\d{4}$/";
回答by Zauker
The better solution is posted by @baba, but the code posted doesn't work fine in certain conditions.
@baba 发布了更好的解决方案，但发布的代码在某些情况下无法正常工作。
For example if you try to validate this date "2019-12-313";
例如，如果您尝试验证此日期“2019-12-313”；
$date = date_parse("2019-12-313");
the function returns this array:
该函数返回这个数组：
Array
(
[year] => 2019
[month] => 12
[day] => 31
[hour] =>
[minute] =>
[second] =>
[fraction] =>
[warning_count] => 0
[warnings] => Array
(
)
[error_count] => 1
[errors] => Array
(
[10] => Unexpected character
)
[is_localtime] =>
)
so, if you perform the command:
所以，如果你执行命令：
checkdate($date['month'], $date['day'], $date['year']);
checkdate will returns a true value because the value of $date['day']is 31 instead of 313.
checkdate 将返回一个真值，因为 的值$date['day']是 31 而不是 313。
to avoid this case maybe you have to add a check to the value of $date['error_count']
为了避免这种情况，也许你必须添加一个检查的值 $date['error_count']
the @baba example updated
@baba 示例已更新
$date = "2019-12-313";
$date = date_parse($date); // or date_parse_from_format("d/m/Y", $date);
if ($date['error_count'] == 0 && checkdate($date['month'], $date['day'], $date['year'])) {
// Valid Date
}
回答by AJ Quick
You received a lot of answers that indicated the RegEx would allow for an answer of 99/99/9999. That can be solved by adding a little more to the RegEx. If you know you'll never have a date outside of the years 1900-2099... you can use a RegEx like this:
您收到了很多答案，这些答案表明 RegEx 将允许 99/99/9999 的答案。这可以通过向 RegEx 添加更多内容来解决。如果你知道你永远不会有 1900-2099 年之外的日期......你可以使用这样的正则表达式：
/^(0[1-9]|[12][0-9]|3[01])[/](0[1-9]|1[012])[/](19|20)\d\d$/
That will validate a date of this format: dd/mm/YYYY
这将验证此格式的日期：dd/mm/YYYY
Between: 01/01/1900 - 31/12/2099
之间：01/01/1900 - 31/12/2099
If you need more years, just add them near the end. |21|22|23|24|25 (would extend it to the year 2599.)
如果您需要更多年，只需在接近尾声时添加它们。|21|22|23|24|25（将其扩展到 2599 年。）
