php PHP通过url上传图片文件

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时间:2020-08-25 05:59:46  来源:igfitidea点击:

PHP upload an image file through url

phpimage-upload

提问by Sanganabasu

I wanna upload an image by url like

我想通过网址上传图片

'C:\wamp\www\reelstubs\app\webroot\img\movies
array(
   'name' => '',
   'type' => '',
   'tmp_name' => '',
   'error' => (int) 4,
   'size' => (int) 0
),
bf522bb76777ba43393b9be5552b263.jpg'

But I want an array like

但我想要一个像

// Your file
$file = 'C:\wamp\www\reelstubs\app\webroot\img\movies
     The enctype attribute of the <form> tag specifies which content-type to use when 
    submitting the form.
    "multipart/form-data" is used when a form requires binary data, like the contents of a
     file, to be uploaded
     so please use the post method for uploading a file because post method can handle unlimited data. but get method not not handle more than 8mb data . 
        <html>
          <body>
                <form action="upload_file.php" method="post"
                enctype="multipart/form-data">
                <label for="file">Filename:</label>
                <input type="file" name="file" id="file"><br>
                <input type="submit" name="submit" value="Submit">
                </form>

                </body>
                </html>
    you can handle the array on upload_file.php page .
upload_file.php

<?php
if ($_FILES["file"]["error"] > 0)
  {
  echo "Error: " . $_FILES["file"]["error"] . "<br>";
  }
else
  {
  echo "Upload: " . $_FILES["file"]["name"] . "<br>";
  echo "Type: " . $_FILES["file"]["type"] . "<br>";
  echo "Size: " . ($_FILES["file"]["size"] / 1024) . " kB<br>";
  echo "Stored in: " . $_FILES["file"]["tmp_name"];
  }
?>
bf522bb76777ba43393b9be5552b263.jpg'; // Open the file to get existing content $data = file_get_contents($file); // New file $new = 'C:\wamp\www\reelstubs\app\webroot\img\movies\newimage.jpg'; // Write the contents back to a new file file_put_contents($new, $data);

Please suggest me how to get that?.

请建议我如何得到那个?

回答by vaibhav

##代码##