xcode 什么是 makeObjectsPerformSelector 的 swift 等价物？
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What is the swift equivalent of makeObjectsPerformSelector?
提问by yumugee
In Objective-C I'm using this code to remove any sub-views:
在 Objective-C 中，我使用此代码删除任何子视图：
[self.view.subviews makeObjectsPerformSelector:@selector(removeFromSuperview)];
But how to use it in swift? I saw apple documentationto use that method in swift
但是如何快速使用它呢？我看到苹果文档在 swift 中使用该方法
func makeObjectsPerformSelector(_ aSelector: Selector)
but when I try it, I get an error: 'AnyObject[]' does not have a member named 'makeObjectsPerformSelector'
但是当我尝试时，我收到一个错误： 'AnyObject[]' does not have a member named 'makeObjectsPerformSelector'
Are there any ways to remove sub-views in swift?
有什么方法可以快速删除子视图？
回答by rob mayoff
Updated for Swift 2.0 (Xcode 7)
为 Swift 2.0 (Xcode 7) 更新
Use forEach:
使用forEach：
self.view.subviews.forEach { subview in
subview.removeFromSuperview()
}
Or like this:
或者像这样：
view.subviews.forEach { let ar: NSArray = [obj1, obj2, obj3]
ar.makeObjectsPerformSelector("someSelector")
.removeFromSuperview() }
回答by Bruce1q
It only works on NSArray and NSMutableArray objects.
它只适用于 NSArray 和 NSMutableArray 对象。
This will work:
这将起作用：
let anNSArray: NSArray = anArrayOfAnyObject
anNSArray.makeObjectsPerformSelector( "someSelector")
Note that if you have an Array<AnyObject>you can freely convert to NSArrayand vise versa.
请注意，如果您有 ，则Array<AnyObject>可以自由转换为NSArray，反之亦然。
回答by FizzBuzz
As of Xcode 7, the full family of performSelector methods are available in Swift, including makeObjectsPerformSelector()for NSArray.
从 Xcode 7 开始，Swift 中提供了完整的 performSelector 方法系列，包括makeObjectsPerformSelector()for NSArray.
