Ruby-on-rails Rails - 获取以小时、分钟和秒为单位的时差
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Rails - Get the time difference in hours, minutes and seconds
提问by Tumas
I'm looking for an idiomatic way to get the time passed since a given date in hours, minutes and seconds.
我正在寻找一种惯用的方法来以小时、分钟和秒为单位获取自给定日期以来经过的时间。
If the given date is 2013-10-25 23:55:00 and the current date is 2013-10-27 20:55:09, the returning value should be 45:03:09. The time_differenceand time_diffgems won't work with this requirement.
如果给定日期是 2013-10-25 23:55:00，当前日期是 2013-10-27 20:55:09，则返回值应该是 45:03:09。该TIME_DIFFERENCE和time_diff宝石不会与此要求的工作。
回答by MrYoshiji
You can try with this:
你可以试试这个：
def time_diff(start_time, end_time)
seconds_diff = (start_time - end_time).to_i.abs
hours = seconds_diff / 3600
seconds_diff -= hours * 3600
minutes = seconds_diff / 60
seconds_diff -= minutes * 60
seconds = seconds_diff
"#{hours.to_s.rjust(2, '0')}:#{minutes.to_s.rjust(2, '0')}:#{seconds.to_s.rjust(2, '0')}"
# or, as hagello suggested in the comments:
# '%02d:%02d:%02d' % [hours, minutes, seconds]
end
And use it:
并使用它：
time_diff(Time.now, Time.now-2.days-3.hours-4.minutes-5.seconds)
# => "51:04:04"
回答by Tumas
time_diff = Time.now - 2.minutes.ago
Time.at(time_diff.to_i.abs).utc.strftime "%H:%M:%S"
=> "00:01:59"
Or if your app is picky about rounding, just replace to_i to round:
或者，如果您的应用对四舍五入很挑剔，只需将 to_i 替换为四舍五入：
Time.at(time_diff.round.abs).utc.strftime "%H:%M:%S"
=> => "00:02:00"
Not sure about the idiomatic part though
虽然不确定惯用的部分
Update: If time difference is expected to be more than 24 hours then the above code is not correct. If such is the case, one could follow the answer of @MrYoshiji or adjust above solution to calculate hours from a datetime object manually:
更新：如果时差预计超过 24 小时，则上述代码不正确。如果是这种情况，可以按照@MrYoshiji 的回答或调整上述解决方案以手动计算日期时间对象的小时数：
def test_time time_diff
time_diff = time_diff.round.abs
hours = time_diff / 3600
dt = DateTime.strptime(time_diff.to_s, '%s').utc
"#{hours}:#{dt.strftime "%M:%S"}"
end
test_time Time.now - 28.hours.ago - 2.minutes - 12.seconds
=> "27:57:48"
test_time Time.now - 8.hours.ago - 2.minutes - 12.seconds
=> "7:57:48"
test_time Time.now - 24.hours.ago - 2.minutes - 12.seconds
=> "23:57:48"
test_time Time.now - 25.hours.ago - 2.minutes - 12.seconds
=> "24:57:48"
回答by Francois
There's a method for that:
有一个方法：
Time.now.minus_with_coercion(10.seconds.ago)
Time.now.minus_with_coercion(10.seconds.ago)
equals 10 (in fact, 9.99..., use .roundif you want a 10).
等于 10（实际上是 9.99...，.round如果您想要 10 ，请使用）。
Source: http://apidock.com/rails/Time/minus_with_coercion
来源：http: //apidock.com/rails/Time/minus_with_coercion
Hope I helped.
希望我有所帮助。
回答by Danny
Look at
看着
how to convert 270921sec into days + hours + minutes + sec ? (ruby)
如何将 270921sec 转换为天 + 小时 + 分钟 + 秒？（红宝石）
which is very similar to your question, just starting from the difference in seconds
这与您的问题非常相似，只是从几秒钟的差异开始
回答by Maged Makled
Once you get the time difference in seconds, you could do something like this
一旦你得到以秒为单位的时差，你可以做这样的事情
Time.at(t).utc.strftime("%H:%M:%S")
Where tis the time difference in seconds
t以秒为单位的时差在哪里
