xcode 我应该如何在 Swift 的标签中获取变量？
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How should I get variable in label in Swift?
提问by AMHD
I'm new to Swift, so I made a new iOS project. I have declared a variable and placed a content into it. Also I have created IBOutletfor label and I tried to get a variable in my label. Swift compiler said: 'UInt32' is not convertible to 'String'.
我是 Swift 的新手，所以我做了一个新的 iOS 项目。我已经声明了一个变量并将内容放入其中。我也IBOutlet为标签创建了，我试图在我的标签中获取一个变量。Swift 编译器说：'UInt32' is not convertible to 'String'.
What's wrong with my code?
我的代码有什么问题？
class ViewController: UIViewController {
@IBOutlet var Mark : UILabel
@IBAction func Rate(sender : UIButton) {
var chibotar = arc4random_uniform(6)
Mark.text = chibotar // error on this line
}
回答by Jean-Philippe Pellet
You need to convert it to a String. You have several ways to do it in this case:
您需要将其转换为字符串。在这种情况下，您有几种方法可以做到：
let chibotar = arc4random_uniform(6) // let instead of var for constants
Mark.text = String(chibotar)
Mark.text = chibotar.description
Mark.text = "\(chibotar)"
回答by PREMKUMAR
Just change the following line
只需更改以下行
Label will display String Values so convert to Sting using following Line.
Label 将显示字符串值，因此使用以下行转换为 Sting。
var chibotar = arc4random_uniform(6)
Mark.text = "\(chibota)"
//(or)
Mark.text = String(chibotar)
It will work
它会工作
