我试图结合这样的功能列表。

我有这个：

Func<int, bool>[] criteria = new Func<int, bool>[3];
criteria[0] = i => i % 2 == 0;
criteria[1] = i => i % 3 == 0;
criteria[2] = i => i % 5 == 0;

我想要这个：

Func<int, bool>[] predicates = new Func<int, bool>[3];
predicates[0] = i => i % 2 == 0;
predicates[1] = i => i % 2 == 0 && i % 3 == 0;
predicates[2] = i => i % 2 == 0 && i % 3 == 0 && i % 5 == 0;

到目前为止，我有以下代码：

Expression<Func<int, bool>>[] results = new Expression<Func<int, bool>>[criteria.Length];

for (int i = 0; i < criteria.Length; i++)
{
    results[i] = f => true;
    for (int j = 0; j <= i; j++)
    {
        Expression<Func<int, bool>> expr = b => criteria[j](b);
        var invokedExpr = Expression.Invoke(
            expr, 
            results[i].Parameters.Cast<Expression>());
        results[i] = Expression.Lambda<Func<int, bool>>(
            Expression.And(results[i].Body, invokedExpr), 
            results[i].Parameters);
    }
}
var predicates = results.Select(e => e.Compile()).ToArray();

Console.WriteLine(predicates[0](6)); // Returns true
Console.WriteLine(predicates[1](6)); // Returns false
Console.WriteLine(predicates[2](6)); // Throws an IndexOutOfRangeException

有人知道我在做什么错吗？

解决方案

据我所知，这是个猜测，但这似乎可以解决此问题：

Func<int, bool>[] criteria = new Func<int, bool>[3]; 
criteria[0] = i => i % 2 == 0; 
criteria[1] = i => i % 3 == 0; 
criteria[2] = i => i % 5 == 0;
Expression<Func<int, bool>>[] results = new Expression<Func<int, bool>>[criteria.Length];
for (int i = 0; i < criteria.Length; i++)
{
    results[i] = f => true; 
    for (int j = 0; j <= i; j++)
    {
        int ii = i;
        int jj = j;
        Expression<Func<int, bool>> expr = b => criteria[jj](b); 
        var invokedExpr = Expression.Invoke(expr, results[ii].Parameters.Cast<Expression>()); 
        results[ii] = Expression.Lambda<Func<int, bool>>(Expression.And(results[ii].Body, invokedExpr), results[ii].Parameters);
    }
} 
var predicates = results.Select(e => e.Compile()).ToArray();

关键是引入" ii"和" jj"(也许只有一个问题，我没有尝试)。我认为我们是在lambda中捕获一个可变变量，因此，当我们最终引用它时，我们会看到后来突变的值，而不是原始值。

无需提取表达式...

Func<int, bool>[] criteria = new Func<int, bool>[3];
    criteria[0] = i => i % 2 == 0;
    criteria[1] = i => i % 3 == 0;
    criteria[2] = i => i % 5 == 0;

    Func<int, bool>[] predicates = new Func<int, bool>[3];

    predicates[0] = criteria[0];
    for (int i = 1; i < criteria.Length; i++)
    {
        //need j to be an unchanging int, one for each loop execution.
        int j = i;

        predicates[j] = x => predicates[j - 1](x) && criteria[j](x);
    }

    Console.WriteLine(predicates[0](6)); //True
    Console.WriteLine(predicates[1](6)); //True
    Console.WriteLine(predicates[2](6)); //False