Ruby-on-rails 基于控制器动作的 Rails 条件 ('if') 语句
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/1329122/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Rails conditional ('if') statements based on controller action
提问by Elliot
There might be a better way to do this, but I'm trying to make an if statement in rails, based on the current action, in a controller (this will be used in a view).
可能有更好的方法来做到这一点，但我正在尝试根据当前操作在控制器中在 rails 中创建一个 if 语句（这将在视图中使用）。
For example, if its the edit page, or the show page, etc. I'd like a different style for something - is there an if statement that can specify this?
例如，如果它是编辑页面，或显示页面等。我想要不同的样式 - 是否有可以指定这一点的 if 语句？
(I need an if statement, because its used in a partial, on multiple pages).
（我需要一个 if 语句，因为它在多个页面上的部分使用）。
Thanks!
谢谢！
Elliot
艾略特
回答by Daniel Vandersluis
The paramshash that is available in the controller contains :controllerand :actionkeys, which specify the controller and action names of the request.
params控制器中可用的哈希包含:controller和:action键，它们指定请求的控制器和操作名称。
Therefore you could say
因此你可以说
if params[:action] == "foo"
# Show stuff for action 'foo'
elsif params[:action] == "bar"
# Show stuff for action 'bar'
elsif ...
# etc.
end
回答by showaltb
It's not good practice IMO to have partials asking what the current controller and action names are. Think "tell, don't ask" (http://www.pragprog.com/articles/tell-dont-ask). That is, rather than having the partial ask it's caller about its state, tellthe partial what you want it to do.
让partials询问当前的控制器和动作名称是什么并不是IMO的好习惯。想想“告诉，不要问”（http://www.pragprog.com/articles/tell-dont-ask）。也就是说，与其让局部询问它的调用者关于它的状态，不如告诉局部你想要它做什么。
One way to do this is by passing variables to the partial through the localsoption:
一种方法是通过locals选项将变量传递给部分：
<%= render :partial => "/common/toolbar", :locals => {:edit => true} %>
Then in the partial:
然后在部分：
<% if defined?(edit) && edit %>
... stuff appropriate to edit mode
<% end %>
回答by Staelen
You can do it this way:
你可以这样做：
class ApplicationController < ActionController::Base
layout :set_layout
def set_layout
case params[:action]
when "foo"
"foo_layout"
when "bar"
"bar_layout"
...
else
"default_layout"
end
end
...
end
hope it helps =)
希望它有帮助 =)
回答by jonnii
You can use layouts for partials too:
您也可以为部分使用布局：
<%= render :partial => 'some_partial', :layout => 'wrap_with_stuff' %>
If you want to work out what layout to use dynamically I'd put that in a helper. So you'd end up with
如果你想确定动态使用什么布局，我会把它放在一个助手中。所以你最终会得到
# In your view
<%= render :partial => 'some_partial', :layout => layout_for_my_partial %>
# In your helper
def layout_for_my_partial
params[:action] == 'show' ? 'show_wrapper' : 'everything_else_wrapper'
end
This will only work in some circumstances, but might be what you're trying to do.
这仅在某些情况下有效，但可能是您想要做的。
See more here.
在这里查看更多。
http://ryandaigle.com/articles/2007/8/3/what-s-new-in-edge-rails-partials-get-layouts
http://ryandaigle.com/articles/2007/8/3/what-s-new-in-edge-rails-partials-get-layouts
