Python 如何减去两个字符串?

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时间:2020-08-19 10:48:38  来源:igfitidea点击:

How to subtract two strings?

pythonstringadditionsubtraction

提问by max smith

I have a long string, which is basically a list like str="lamp, bag, mirror,"(and other items)

我有一个很长的字符串,它基本上是一个类似str="lamp, bag, mirror,"(和其他项目)的列表

I was wondering if I can add or subtract some items, in other programming languages I can easily do: str=str-"bag,"and get str="lamp, mirror,"this doesnt work in python (I'm using 2.7 on a W8 pc)

我想知道我是否可以添加或减去一些项目,在其他编程语言中我可以轻松做到:str=str-"bag,"并且str="lamp, mirror,"在 python 中不起作用(我在 W8 pc 上使用 2.7)

Is there a way to split the string across say "bag," and somehow use that as a subtraction? Then I still need to figure out how to add.

有没有办法将字符串拆分为“包”,然后以某种方式将其用作减法?然后我还需要弄清楚如何添加。

回答by óscar López

You can do this as long as you use well-formed lists:

只要您使用格式良好的列表,就可以执行此操作:

s0 = "lamp, bag, mirror"
s = s0.split(", ") # s is a list: ["lamp", "bag", "mirror"]

If the list is not well-formed, you can do as follows, as suggested by @Lattyware:

如果列表格式不正确,您可以按照@Lattyware 的建议执行以下操作:

s = [item.strip() for item in s0.split(',')]

Now to delete the element:

现在删除元素:

s.remove("bag")
s
=> ["lamp", "mirror"]

Either way - to reconstruct the string, use join():

无论哪种方式 - 要重建字符串,请使用join()

", ".join(s)
=> "lamp, mirror"

A different approach would be to use replace()- but be careful with the string you want to replace, for example "mirror"doesn't have a trailing ,at the end.

一种不同的方法是使用replace()- 但要小心要替换的字符串,例如"mirror"末尾没有尾随,

s0 = "lamp, bag, mirror"
s0.replace("bag, ", "")
=> "lamp, mirror"

回答by dare

you should convert your string to a list of string then do what you want. look

您应该将字符串转换为字符串列表,然后执行您想要的操作。看

my_list="lamp, bag, mirror".split(',')
my_list.remove('bag')
my_str = ",".join(my_list)

回答by Joran Beasley

you could also just do

你也可以这样做

print "lamp, bag, mirror".replace("bag,","")

回答by badc0re

Using regular expression example:

使用正则表达式示例:

import re

text = "lamp, bag, mirror"
word = "bag"

pattern = re.compile("[^\w]+")
result = pattern.split(text)
result.remove(word)
print ", ".join(result)

回答by Zaka Elab

How about this?:

这个怎么样?:

def substract(a, b):                              
    return "".join(a.rsplit(b))

回答by Rohan Amrute

If you have two strings like below:

如果你有两个像下面这样的字符串:

t1 = 'how are you'
t2 = 'How is he'

and you want to subtract these two strings then you can use the below code:

如果您想减去这两个字符串,则可以使用以下代码:

l1 = t1.lower().split()
l2 = t2.lower().split()
s1 = ""
s2 = ""
for i in l1:
  if i not in l2:
    s1 = s1 + " " + i 
for j in l2:
  if j not in l1:
    s2 = s2 + " " + j 

new = s1 + " " + s2
print new

Output will be like:

输出将类似于:

are you is he

你是他吗

回答by J. Doe

Using the following you can add more words to remove (["bag", "mirror", ...])

使用以下内容,您可以添加更多单词以删除 ( ["bag", "mirror", ...])

(s0, to_remove) = ("lamp, bag, mirror", ["bag"])
s0 = ", ".join([x for x in s0.split(", ") if x not in to_remove])
=> "lamp, mirror"

回答by Dengs

from re import sub

def Str2MinusStr1 (str1, str2, n=1) :
    return sub(r'%s' % (str2), '', str1, n)

Str2MinusStr1 ('aabbaa', 'a')  
# result 'abbaa'

Str2MinusStr1 ('aabbaa', 'ab')  
# result 'abaa'

Str2MinusStr1 ('aabbaa', 'a', 0)  
# result 'bb'

# n = number of occurences. 
# 0 means all, else means n of occurences. 
# str2 can be any regular expression.