你如何在 Scala 中输入类型转换 Char/Int?

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时间:2020-10-22 02:34:31  来源:igfitidea点击:

How do you type cast Char/Int in Scala?

scalacasting

提问by CanisUrsa

I am having issues getting this cast to work.

我在让这个演员工作时遇到问题。

The compiler tells me value aNumberis not a member of object Char

编译器告诉我 valueaNumber不是 object 的成员Char

def runCastTest() {  
  val aNumber = 97  
  val aChar = (Char)aNumber

  println(aChar) // Should be 'a'  
}

What am I doing wrong?

我究竟做错了什么?

回答by fedesilva

You are not casting. With (Char)aNumberyou are trying to invoke a method aNumberin the object Char:

你不是在铸造。当(Char)aNumber您尝试调用aNumber对象 Char 中的方法时:

scala> val aNumber = 97
aNumber: Int = 97

scala> val aChar = (Char)aNumber
<console>:5: error: value aNumber is not a member of object Char
        val aChar = (Char)aNumber
                          ^

You can do

你可以做

scala> aNumber.asInstanceOf[Char]
res0: Char = a

or as Nicolas suggested call toCharon the Int instance:

或者像 Nicolas 建议调用toCharInt 实例:

scala> aNumber.toChar
res1: Char = a

回答by Nicolas

As everything is an Object in scala, you should use aNumber.toChar.

由于在 Scala 中一切都是对象,因此您应该使用aNumber.toChar.