Python 列表函数参数名称
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Python list function argument names
提问by Bemmu
Is there a way to get the parameter names a function takes?
有没有办法获取函数采用的参数名称？
def foo(bar, buz):
pass
magical_way(foo) == ["bar", "buz"]
采纳答案by Alex Martelli
Use the inspectmodule from Python's standard library (the cleanest, most solid way to perform introspection).
使用Python 标准库中的检查模块（最干净、最可靠的内省方式）。
Specifically, inspect.getargspec(f)returns the names and default valuesof f's arguments -- if you only want the names and don't care about special forms *a, **k,
具体来说，inspect.getargspec(f)返回名称和默认值的f的参数-如果你只是想名字和不关心特殊形式*a，**k，
import inspect
def magical_way(f):
return inspect.getargspec(f)[0]
completely meets your expressed requirements.
完全满足您表达的要求。
回答by John La Rooy
>>> import inspect
>>> def foo(bar, buz):
... pass
...
>>> inspect.getargspec(foo)
ArgSpec(args=['bar', 'buz'], varargs=None, keywords=None, defaults=None)
>>> def magical_way(func):
... return inspect.getargspec(func).args
...
>>> magical_way(foo)
['bar', 'buz']
