在 Python 中为函数别名
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Alias a function in Python
提问by Randomblue
I would like a copy of the printfunction that is called debug. How can I alias a function in Python?
我想要一份print名为的函数的副本debug。如何在 Python 中为函数设置别名？
采纳答案by Pavel Anossov
You can simply assign debug = printin Python 3.
您可以简单地debug = print在 Python 3 中赋值。
In Python 2 printisn't a function. There no way to give yourself a debugstatement that works exactly like print(print 1,, print 1 >> sys.stderretc.). Best you can do is write a wrapper around the printstatement:
在 Python 2print中不是函数。有没有办法给自己debug的作品完全一样的语句print（print 1,，print 1 >> sys.stderr等等）。你能做的最好的事情就是在print语句周围写一个包装器：
def debug(s):
print s
You can also disable the printstatement and use the Python 3 version:
您还可以禁用该print语句并使用 Python 3 版本：
from __future__ import print_function
debug = print
If you do this, you cannot use the statement version (print x) anymore. It's probably the way to go if you're not breaking any old code.
如果这样做，则不能再使用语句版本 ( print x)。如果您不破坏任何旧代码，这可能是要走的路。
回答by Steve Mayne
In Python 2.x you can do:
在 Python 2.x 中，您可以执行以下操作：
def debug(s):
print(s)
In 3.x you can just use assignment:
在 3.x 中你可以只使用赋值：
debug = print
回答by Andbdrew
You can just define a new function debuglike:
您可以定义一个新函数，debug例如：
def debug(text):
print text
回答by Weetu
It depends on your version of Python. Python 3 simply allows you to do this:
这取决于您的 Python 版本。Python 3 只允许你这样做：
debug = print
However, older versions consider printto be a built-in keyword, so you have to wrap it in your own function:
但是，旧版本认为print是内置关键字，因此您必须将其包装在您自己的函数中：
def debug(msg):
print(msg)
回答by jtpereyda
The defmethod has the advantage that tracebacks more clearly identify the alias. This could help a user who says, "What's 'print'?" if they only use debug(the alias):
该def方法的优点是回溯更清楚地识别别名。这可以帮助那些说“' print'是什么？”的用户。如果他们只使用debug（别名）：
>>> def f():
... print x
>>> g = f
>>> g()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<stdin>", line 2, in f
NameError: global name 'x' is not defined
>>>
>>> def h():
... return f()
...
>>> h()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<stdin>", line 2, in h
File "<stdin>", line 2, in f
NameError: global name 'x' is not defined
