java 如何在Java中获取List的最早日期？
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How to get the earliest date of a List in Java?
提问by mffm
I have an ArrayList which stores 0...4 Dates.
我有一个存储 0...4 个日期的 ArrayList。
The amount of Dates in the list depends on a Business logic.
列表中的日期数量取决于业务逻辑。
How can I get the earliest date of this list? Of course I can build iterative loops to finally retrieve the earliest date. But is there a 'cleaner'/ quicker way of doing this, especially when considering that this list can grow on a later perspective?
我怎样才能得到这个列表的最早日期？当然，我可以构建迭代循环来最终检索最早的日期。但是有没有一种“更干净”/更快的方法来做到这一点，尤其是考虑到这个列表可以在以后的角度增长时？
回答by Andy Turner
java.util.Dateimplements Comparable<Date>, so you can simply use:
java.util.Date实现Comparable<Date>，所以你可以简单地使用：
Date minDate = Collections.min(listOfDates);
This relies on there being at least one element in the list.
这依赖于列表中至少有一个元素。
回答by ΦXoc? ? Пepeúpa ツ
If you dont mind to change the insertion order then sort the list and get the elemeent at index 0
如果您不介意更改插入顺序，则对列表进行排序并在索引 0 处获取元素
回答by JF Meier
SortedSet
SortedSet
Depending on your application you can think about using a SortedSet(like TreeSet). This allows you to change the collection and always receive the lowest element easily.
根据您的应用程序，您可以考虑使用SortedSet（如TreeSet）。这允许您更改集合并始终轻松接收最低元素。
Adding elements to the collection is more expensive, though.
但是，向集合中添加元素的成本更高。
