Java 二元运算符“<=”的错误操作数类型
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bad operand types for binary operator '<='
提问by user3470113
I can't seem to figure out why i'm getting this error. I've tried putting everything in parenthesis and that helped the problem a little bit. It would be great if I could get some help.
我似乎无法弄清楚为什么我会收到此错误。我试过把所有东西都放在括号里，这对问题有一点帮助。如果我能得到一些帮助，那就太好了。
error: bad operand types for binary operator '<='
错误：二元运算符“<=”的错误操作数类型
Code :
代码 ：
public void merge(String[] result, String[] nameA, String[] nameB)
{
int i1 = 0; // index into nameA array
int i2 = 0; // index into nameB array
for (int i = 0; i < result.length; i++)
{
if (i2 >= nameB.length || (i1 < nameA.length && nameA[i1] <= nameB[i2]))
{
result[i] = nameA[i1]; // take from nameA
i1++;
}
else
{
result[i] = nameB[i2]; // take from nameB
i2++;
}
}
}
采纳答案by luksch
In addition to the answers of Luiggi Mendoza and Ivaylo Strandjev I like to point out that if you only want to make sure the strings differ, you can use equals like this:
除了 Luiggi Mendoza 和 Ivaylo Strandjev 的答案之外，我想指出的是，如果您只想确保字符串不同，您可以像这样使用 equals：
if (i2 >= nameB.length || (i1 < nameA.length && !nameA[i1].equals(nameB[i2])))
回答by Luiggi Mendoza
<=and >=operators are for numeric primitive types like intor double. To compare Strings, use compareTomethod.
<=和>=运算符用于数字原始类型，例如intor double。要比较Strings，请使用compareTo方法。
nameA[i1].compareTo(nameB[i2]) < 0
If you want to compare Strings by length, then use <=operator on String#lengthinstead:
如果要按String长度比较s，请改用<=运算符 on String#length：
nameA[i1].length() <= nameB[i2].length()
回答by Ivaylo Strandjev
In order to compare Strings in Java you need to call the method compareTo. Have a look at the Comparableinterface that Stringimplements.
为了String在 Java 中比较s，您需要调用方法compareTo。查看实现的Comparable接口String。
