Java HttpPost：InputDispatcher：“通道不可恢复地损坏，将被处理！” 在 Nexus 7 上
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HttpPost: InputDispatcher: "Channel is unrecoverably broken and will be disposed!" on Nexus 7
提问by mylord
On Nexus 7 (4.3), and not on my older device, LG Optimus 3d (Android 2.2), when I do HttpPost, I get this
在 Nexus 7 (4.3) 上，而不是在我的旧设备 LG Optimus 3d (Android 2.2) 上，当我执行 HttpPost 时，我得到了这个
E/InputDispatcher﹕ channel '4273f7b0 ... MainActivity (server)' ~ Channel is unrecoverably broken and will be disposed!
E/InputDispatcher: channel '4273f7b0 ... MainActivity (server)' ~ 通道不可恢复地损坏，将被处理！
People have mentioned a possible memory leak. See **. However, this problem happens right away on startup when I try the HttpPost. Is it still likely a memory leak?
人们提到了可能的内存泄漏。看 **。但是，当我尝试 HttpPost 时，这个问题会在启动时立即发生。它仍然可能是内存泄漏吗？
Here is how I'm doing the HttpPost:
这是我如何做 HttpPost：
public void server_addUserGetId()
{
String url = GS.baseUrl() + "/users";
HttpPost theHttpPost = new HttpPost(url);
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("dId", s_UserInfo.getInstance().m_device_id ));
try {
theHttpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
HttpPostAsync theHttpPostAsync = new HttpPostAsync(new OnPostExecuteHandler() {
@Override
public void handlePostExecute(Object oHttpResponse) {
HttpResponse theHttpResponse = (HttpResponse) oHttpResponse;
JSONObject jo = GS.getJSONObject(theHttpResponse.getEntity());
try {
s_UserInfo.getInstance().m_user_id = jo.getString("_id");
} catch (JSONException e) {
e.printStackTrace();
}
}
});
theHttpPostAsync.execute(theHttpPost);
return;
}
Here is my HttpPostAsync task:
这是我的 HttpPostAsync 任务：
public class HttpPostAsync extends AsyncTask<HttpPost, Integer, HttpResponse>
{
private HttpPost m_HttpPost;
private HttpResponse m_HttpResponse;
private OnPostExecuteHandler m_OnPostExecuteHandler;
public HttpPostAsync(OnPostExecuteHandler listener)
{
m_OnPostExecuteHandler = listener;
}
protected HttpResponse doInBackground(HttpPost ... args)
{
m_HttpPost = args[0];
if(GS.dl>5) Log.d("GRA: HttpPostAsync", "doInBackground: Thread.currentThread().getId()=" + Thread.currentThread().getId());
m_HttpResponse = visit(m_HttpPost);
return m_HttpResponse;
}
protected void onProgressUpdate(Integer... progress) {
}
protected void onPostExecute(Long result) {
if(GS.dl>5) Log.d("GRA: HttpPostAsync", "onPostExecute: Thread.currentThread().getId()=" + Thread.currentThread().getId());
if(GS.dl>5) Log.d("GRA: HttpPostAsync", "onPostExecute: result=" + result);
//if(GS.dl>5) Log.d("GRA: HttpPostAsync", "onPostExecute: m_HttpEntity="+m_HttpEntity);
m_OnPostExecuteHandler.handlePostExecute(m_HttpResponse);
}
public HttpResponse visit(HttpPost theHttpPost)
{
HttpResponse response = null;
try {
// Create a new HttpClient and Post Header
HttpClient httpclient = new DefaultHttpClient();
// Execute HTTP Post Request
response = httpclient.execute(theHttpPost);
} catch (IOException e) {
e.printStackTrace();
Log.d("HttpPostAsync.java", "IOException e=" + e);
// TODO Auto-generated catch block
}
return response;
}
}
Any ideas?
有任何想法吗？
I read on an SO answer* it might have to do with the ArrayList initialization, so I've also tried initializing like this, with 1, in the ArrayList, but the problem persists:
我读了一个 SO answer* 它可能与 ArrayList 初始化有关，所以我也尝试过这样初始化，在 ArrayList 中使用 1，但问题仍然存在：
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(1);
*: SO answer that didn't totally relate/help: App has stopped working Android
*：不完全相关的答案/帮助： 应用程序已停止运行 Android
** memory leak related? http://android-developers.blogspot.com/2011/03/memory-analysis-for-android.html
** 内存泄漏相关？http://android-developers.blogspot.com/2011/03/memory-analysis-for-android.html
回答by Solution
回答by Hymanie_Hung
I met same troubles in 2 days ago for Android, not pure Java, this asnwer let you reference only.I solve it now.I am Taiwanese, I am glad to answer here once more. Do you ever use UI new thread? Do not double use UI new thread look like sandwich. It should cause memory leaks.
我在两天前遇到了同样的麻烦，Android，不是纯Java，这个答案仅供参考。我现在解决了。我是台湾人，很高兴再次在这里回答。你有没有使用过 UI 新线程？不要重复使用 UI 新线程看起来像三明治。它应该会导致内存泄漏。
in a short sentence, a main thread could have many UI threads to do many work, but if one sub thread(not main thread) own a UI thread inside, maybe sub thread work done, but its kid ~ UI thread has not finish work, this will case memory leaks.
简而言之，一个主线程可以有很多UI线程来做很多工作，但是如果一个子线程（不是主线程）在里面拥有一个UI线程，也许子线程工作完成了，但是它的孩子~UI线程没有完成工作，这会导致内存泄漏。
For example...for Fragment & UI application...this will cause memory leaks.
例如...对于 Fragment & UI 应用程序...这将导致内存泄漏。
getActivity().runOnUiThread(new Runnable(){
public void run() {
ShowDataScreen();
getActivity().runOnUiThread(new Runnable(){
public void run() {
Toast.makeText(getActivity(), "This is error way",Toast.LENGTH_SHORT).show();
}});// end of No.2 UI new thread
}});// end of No.1 UI new thread
My solution is rearrange as below:
我的解决方案是重新排列如下：
getActivity().runOnUiThread(new Runnable(){
public void run() {
ShowDataScreen();
}});// end of No.1 UI new thread
getActivity().runOnUiThread(new Runnable(){
public void run() {
Toast.makeText(getActivity(), "This is correct way",Toast.LENGTH_SHORT).show();
}});// end of No.2 UI new thread
for you reference.
供你参考。
