Python 相对导入脚本向上两级
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Python relative-import script two levels up
提问by Luke Taylor
I've been struggling with imports in my package for the last hour.
在过去的一个小时里，我一直在为我的包中的导入而苦苦挣扎。
I've got a directory structure like so:
我有一个这样的目录结构：
main_package
|
| __init__.py
| folder_1
| | __init__.py
| | folder_2
| | | __init__.py
| | | script_a.py
| | | script_b.py
|
| folder_3
| | __init__.py
| | script_c.py
I want to access code in script_b.pyas well as code from script_c.pyfrom script_a.py. How can I do this?
我想在访问代码script_b.py从以及代码script_c.py从script_a.py。我怎样才能做到这一点？
If I put a simple import script_binside script_a.py, when I run
如果我import script_b在里面放一个简单的script_a.py，当我跑
from main_package.folder_1.folder_2 import script_b
I am met with an
我遇到了一个
ImportError: no module named "script_b"
For accessing script_c.py, I have no clue. I wasn't able to find any information about accessing files two levels up, but I know I can import files one level up with
对于访问script_c.py，我不知道。我无法找到有关访问上两级文件的任何信息，但我知道我可以导入上一级文件
from .. import some_module
How can I access both these files from script_a.py?
我怎样才能访问这两个文件script_a.py？
回答by tobspr
To access script_c and script_b from script_a, you would use:
要从 script_a 访问 script_c 和 script_b，您可以使用：
from ...folder_3 import script_c
from . import script_b
Or if you use python3, you can import script_b from script_a by just using:
或者，如果您使用 python3，则只需使用以下命令即可从 script_a 导入 script_b：
import script_b
However, you should probably use absolute imports:
但是，您可能应该使用绝对导入：
from mypackage.folder_3 import script_c
from mypackage.folder1.folder2 import script_b
Also see: Absolute vs Relative imports
另请参阅：绝对与相对导入
