如何在 linux 中获取给定语言环境的语言名称

Howto get the language name for a given locale in linux

提问by Dushara

This is pretty much This questionwith a bit more information. My goal is to work out the languages installed in the system.

这几乎是这个问题，有更多信息。我的目标是找出系统中安装的语言。

The following command

以下命令

locale -a 

displays all the languages (in a format such as en_AU.utf8). This seems to correspond to the contents of /usr/lib/locale.

显示所有语言（以 en_AU.utf8 等格式）。这似乎对应于 /usr/lib/locale 的内容。

Furthermore, invoking

此外，调用

LANG=fr_FR.utf8 locale -ck LC_IDENTIFICATION

Gives information of that particular locale which includes the language name (Which in this case is French).

提供该特定语言环境的信息，其中包括语言名称（在本例中为法语）。

This seems to be the information contained in /usr/lib/locale/fr_FR.utf8/LC_IDENTIFICATION.

这似乎是/usr/lib/locale/fr_FR.utf8/LC_IDENTIFICATION 中包含的信息。

Is there a way (maybe an API call) to obtain this info? I looked at the source of the locale utility but it uses a private struct.

有没有办法（也许是 API 调用）来获取这些信息？我查看了 locale 实用程序的源代码，但它使用了私有结构。

采纳答案by Dushara

Thanks to Yasir. This is exactly what I wanted:

感谢亚西尔。这正是我想要的：

#include <langinfo.h>

char *s;
s = getenv("LANG");
if (s == NULL) 
    printf("LANG is not set");
else {
    setlocale(LC_ALL, s);
    printf(nl_langinfo(_NL_IDENTIFICATION_LANGUAGE));
}

回答by Yasir Arsanukaev

I think, you could just get environment variables, using, for example, getenv(3), thus you would want to pass it the name of variable, e. g.:

我认为，您可以使用例如，获取环境变量，getenv(3)因此您希望将变量的名称传递给它，例如：

char *s;
s = getenv("LANG");
if (s == NULL) 
    printf("LANG is not set");
else
    printf(s);