bash 如何在awk中打印变量
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How to print variable inside awk
提问by Sharat Chandra
I want the awk to interpret the variable as follows
我希望 awk 解释变量如下
#!/bin/bash
file=tau
f=2.54
order=even
awk '{sum+=}; END {print '${file}_${f}_${order}_v1.xls', sum/NR}'
${file}_${f}_${order}_v1.xls >> safe/P-state-summary.xls
I want the desired output as follows -
我想要如下所需的输出 -
tau_2.54_even_v1.xls sum/NR
Can anybody help me out with this ?
有人可以帮我解决这个问题吗？
回答by Matt Ryall
First, you need to exportenvironment variables if you want them to be passed in the environment of a child process like awk.
首先，export如果您希望在子进程的环境中传递环境变量，例如awk.
Second, you can use ENVIRON["name"]to get an environment variable in awk. So the following works for me:
其次，您可以使用ENVIRON["name"]在awk. 所以以下对我有用：
#!/bin/bash
export file=tau
export f=2.54
export order=even
awk '{sum+=}; END {print ENVIRON["file"] "_" ENVIRON["f"] "_" ENVIRON["order"] "_v1.xls", sum/NR}'
回答by TheBonsai
Don't forget that you can set "AWK variables" on commandline
不要忘记您可以在命令行上设置“AWK 变量”
awk -v FOO=bar '...<AWK code that uses the AWK variable FOO>...'
回答by DigitalRoss
I think this is what you want:
我认为这就是你想要的：
#!/bin/bash
file=tau
f=2.54
order=even
awk "{sum+=$2}; END {print \"${file}_${f}_${order}_v1.xls\", sum/NR}" \
${file}_${f}_${order}_v1.xls >> safe/P-state-summary.xls
回答by Sharat Chandra
Well I used a mixture of the above solutions and got it working with this
好吧，我使用了上述解决方案的混合物，并使用了它
printf "\n${file}_${f}_${order}_v1.xls " >> Safe/P-state-summary.xls
awk '{sum+=}; END {print sum/NR}' ${file}_${f}_${order}_v1.xls >> Safe/P-state-summary.xls
