Python Beautifulsoup 获取跨度内容
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Beautifulsoup get span content
提问by add-semi-colons
I have parsed html page: using beautifulsoup
我已经解析了 html 页面： using beautifulsoup
user_page = urllib2.urlopen(user_url)
souping_page = bs(user_page)
badges = souping_page.body.find('div', attrs={'class': 'badges'})
after this my badgesobject looks like this:
在此之后，我的badges对象如下所示：
<span><span title="9 gold badges"><span class="badge1"></span><span class="badgecount">9</span></span><span title="38 silver badges"><span class="badge2"></span><span class="badgecount">38</span></span><span title="56 bronze badges"><span class="badge3"></span><span class="badgecount">56</span></span></span>
Now I want to extract example 9 gold badges, 38 silver badgesfrom this, I tried to use badges.span.spanbut that doesn't work.
现在我想从中提取 example 9 gold badges，38 silver badges我尝试使用badges.span.span但不起作用。
采纳答案by alecxe
Get the parent spanfrom badges, find all top-level spans inside by using find_all()with recursive=False:
span从获取父badges级，通过使用find_all()with找到所有顶级跨度recursive=False：
from bs4 import BeautifulSoup
page = """<div class="badges">
<span>
<span title="9 gold badges"><span class="badge1"></span><span class="badgecount">9</span></span>
<span title="38 silver badges"><span class="badge2"></span><span class="badgecount">38</span></span>
<span title="56 bronze badges"><span class="badge3"></span><span class="badgecount">56</span></span>
</span>
</div>"""
soup = BeautifulSoup(page)
badges = soup.body.find('div', attrs={'class': 'badges'})
for span in badges.span.find_all('span', recursive=False):
print span.attrs['title']
prints:
印刷：
9 gold badges
38 silver badges
56 bronze badges
Hope that helps.
希望有帮助。
