python Python线程退出代码
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Python thread exit code
提问by Jiayao Yu
Is there a way to tell if a thread has exited normally or because of an exception?
有没有办法判断一个线程是正常退出还是因为异常退出？
回答by A. Coady
As mentioned, a wrapper around the Thread class could catch that state. Here's an example.
如前所述，围绕 Thread 类的包装器可以捕获该状态。这是一个例子。
>>> from threading import Thread
>>> class MyThread(Thread):
def run(self):
try:
Thread.run(self)
except Exception as err:
self.err = err
pass # or raise err
else:
self.err = None
>>> mt = MyThread(target=divmod, args=(3, 2))
>>> mt.start()
>>> mt.join()
>>> mt.err
>>> mt = MyThread(target=divmod, args=(3, 0))
>>> mt.start()
>>> mt.join()
>>> mt.err
ZeroDivisionError('integer division or modulo by zero',)
回答by samoz
You could set some global variable to 0 if success, or non-zero if there was an exception. This is a pretty standard convention.
如果成功，您可以将某个全局变量设置为 0，如果出现异常，则可以将其设置为非零。这是一个非常标准的约定。
However, you'll need to protect this variable with a mutex or semaphore. Or you could make sure that only one thread will ever write to it and all others would just read it.
但是，您需要使用互斥锁或信号量来保护此变量。或者您可以确保只有一个线程会写入它，而所有其他线程都会读取它。
回答by user9876
Have your thread function catch exceptions. (You can do this with a simple wrapper function that just calls the old thread function inside a try...exceptor try...except...elseblock). Then the question just becomes "how to pass information from one thread to another", and I guess you already know how to do that.
让您的线程函数捕获异常。（您可以使用一个简单的包装函数来完成此操作，该函数仅在try...except或try... except...else块中调用旧线程函数）。那么问题就变成了“如何将信息从一个线程传递到另一个线程”，我想您已经知道如何做到这一点了。
