ios 使用 NSPredicate 用数组搜索数组
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Using NSPredicate to search an array with an array
提问by quantum
I have an array of Cardobjects (NSObjects), each with a field called tags, which is an NSArray of NSStrings.
我的阵列Card对象（NSObjects），各自具有被称为字段tags，这是NSString的的一个NSArray。
I would then like to split up the user's search term into an array called keywordsof strings by componentsSeparatedByString, then use NSPredicate to filter my array of Cards based on which elements have tags containing at least 1 keyword in keywords.
我会再像分割用户的搜索术语称为数组keywords的字符串componentsSeparatedByString，然后使用NSPredicate来筛选我在此基础上的元素都包含至少1关键字标签卡的阵列keywords。
I hope that's not too convoluted! I've tried using the NSPredicate INclause to no avail. How should I do this?
我希望这不会太复杂！我试过使用 NSPredicateIN子句无济于事。我该怎么做？
回答by Vignesh
Considering arraycontains card Object.
考虑array包含卡片对象。
NSArray *keyWordsList = [keywords componentSeparatedByString:@","];
[array filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"ANY %K IN %@",@"tags",keyWordsList]]
EDIT:
编辑：
To search partially you can use LIKE operator.
要部分搜索，您可以使用 LIKE 运算符。
[array filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"ANY %K LIKE[cd] %@",@"tags",[partialkeyWord stringByAppendingString:@"*"]]]
回答by Paul de Lange
Don't kill me if this isn't exactly right, but something like this will work.
如果这不完全正确，请不要杀我，但这样的事情会起作用。
NSArray* arrayOfCards = [NSArray array];
NSArray* keywords = [NSArray array];
NSPredicate* containsAKeyword = [NSPredicate predicateWithBlock: ^BOOL(id evaluatedObject, NSDictionary *bindings) {
Card* card = (Card*)evaluatedObject;
NSArray* tagArray = card.tags;
for(NSString* tag in tagArray) {
if( [keywords containsObject: tag] )
return YES;
}
return NO;
}];
NSArray* result = [arrayOfCards filteredArrayUsingPredicate: containsAKeyword];
